Irregular sculpture hanging from two thin vertical wires

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Homework Help Overview

The discussion revolves around a physics problem involving an irregular sculpture weighing 358 N, which is suspended from two vertical wires. The setup includes the distances between the wires and the location of the sculpture's center of gravity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equilibrium conditions of the sculpture, including the balance of forces and torques. There are mentions of free body diagrams (FBDs) and the application of Newton's laws. Some participants express uncertainty about their reasoning and seek clarification on their approach.

Discussion Status

The discussion is ongoing, with participants providing hints and exploring the implications of equilibrium. There is acknowledgment of the need for the original poster to engage more deeply with the problem, and some guidance has been offered regarding the setup of equations.

Contextual Notes

Participants note the importance of maintaining equilibrium in the system and question the setup of the equations related to the forces acting on the sculpture. There is a focus on ensuring that the original poster understands the concepts rather than simply providing answers.

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i have been stuck on this question for two days, can anyone help!

A museum of modern art is displaying an irregular 358 N sculpture by hanging it from two thin vertical wires, A and B, that are 1.25 m apart . The center of gravity of this piece of art is located 48.0 cm from its extreme right tip.

YF-11-40.jpg


Find the tension in the wire A.

Find the tension in the wire B.
 
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Two days? Show us the FBDs you've drawn during this period of work...
 
I think it's like you have to say that since the object is in equilibrium, there are no external unbalanced forces or torques acting on the system. That means F=ma in the vertical direction (up is +ve) gives you Ta + Tb = << edited out by berkeman >> . Then, assigning counter-clockwise as +ve and using the center of gravity as the point about which to sum moments, you have Tau(net) = 0 = << edited out by berkeman >> . Now we have two equations and two unknowns. Not hard to solve from there. I think that's how you do it, but I'm still learning too, so I'm not sure. :shy: Just trying to help out as much I can. :smile:
 
Last edited by a moderator:
Gyro said:
I think it's like you have to say that since the object is in equilibrium, there are no external unbalanced forces or torques acting on the system. That means F=ma in the vertical direction (up is +ve) gives you Ta + Tb = << edited out by berkeman >> . Then, assigning counter-clockwise as +ve and using the center of gravity as the point about which to sum moments, you have Tau(net) = 0 = << edited out by berkeman >> . Now we have two equations and two unknowns. Not hard to solve from there. I think that's how you do it, but I'm still learning too, so I'm not sure. :shy: Just trying to help out as much I can. :smile:

Thanks for the help, Gyro. Please remember to only provide hints on homework/coursework questions. We need to have the OP do the bulk of the work.
 
I'm sorry about that. Won't happen again.
 
Gyro said:
I'm sorry about that. Won't happen again.

No worries. Even with the work deleted, you have still provided useful hints to the OP. Thanks.
 
Is this set up correct?

TA + TB - mg = 0 = Ttot (since the object is in equilibrium)

Im not wure where to go from here or if this is even right
 

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