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## Homework Statement

A 27-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire. What horizontal force would be necessary to displace its position 0.15m to one side?

## Homework Equations

[/B]

F*x = m*g*h

## The Attempt at a Solution

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I tried to find the height the chandelier elevates. With the pythogorean theorem, 4 becomes hypothenus, and 0.15 becomes cathetus.

x^2 + 0.15^2 = 4^2

x = 3.99718651

h = 4 - 3.99718651

h = 0.00281349

Fx = mgh

F*0.15 = 27*9.8*0.00281349

F = 4.96299636

When you multiply my result with 2, you get 9.92599272, which is the correct answer according to the book.(9.9N)