- #1
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Homework Statement
A 27-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire. What horizontal force would be necessary to displace its position 0.15m to one side?
Homework Equations
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F*x = m*g*h
The Attempt at a Solution
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I tried to find the height the chandelier elevates. With the pythogorean theorem, 4 becomes hypothenus, and 0.15 becomes cathetus.
x^2 + 0.15^2 = 4^2
x = 3.99718651
h = 4 - 3.99718651
h = 0.00281349
Fx = mgh
F*0.15 = 27*9.8*0.00281349
F = 4.96299636
When you multiply my result with 2, you get 9.92599272, which is the correct answer according to the book.(9.9N)