Is 66° Below the Horizontal? Solve the Equation

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SUMMARY

The discussion centers on determining the correct angle to use in the equation for calculating magnetic flux when given an angle of 66 degrees below the horizontal. The magnetic field strength is specified as 48x10-6T, and the problem involves a wedding ring with a diameter of 2.2 cm. The key conclusion is that the angle θ used in the equation should be 24 degrees, as it represents the angle between the magnetic field and the normal to the ring, not the angle below the horizontal.

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Homework Statement



if a questions states that the angle of 66 degrees is below the horizontal is that the angle I put into the equation

Homework Equations





The Attempt at a Solution

 
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Hi cerium! :smile:
cerium said:
if a questions states that the angle of 66 degrees is below the horizontal is that the angle I put into the equation

erm :redface:what equation? :wink:
 
Sorry missed out the most important part
ABcos(theata) can't find symbol for that.
the question asked you to find magnetic flux I have worked out A and B but I am unsure what it means when it says : the angle is 66 degrees below the horizontal:
Thanks
 
Hi cerium! :smile:

(have a theta: θ and a degree: º :wink:)

(i still don't understand what this is about :redface:)

I assume that θ is the angle between A and B,

so what are A and B?
 
The Earth's magnetic field at a certian location in the uk has a magnitude of 48x10-6T and is directed at 66 degrees below the horizontal.
Determine the magnitude of flux of the Earth's magnetic field through a wedding ring of diameter 2.2cm when the ring is held in the horizontal plane.
What is the magnitude of flux change when the ring is flipped through 180 degrees.

It the angle that is bothering me
Thanks
 
ah!

so B is 66º below the horizontal.

ok, the flux through a surface (or through its boundary) is greatest when the surface is perpendicular to the field, ie when the normal to the surface is parallel to the field.

So θ is the angle between B and the normal to the ring. :wink:
 
I see so I would be using cos24 not cos66
 
Yes. :smile:
 

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