Is a Function Continuous If It Maps Closure to Closure in Metric Spaces?

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SUMMARY

A function f: X -> Y between metric spaces (X, d1) and (Y, d2) is continuous if and only if the image of the closure of any subset A of X is contained within the closure of the image of A, denoted as f(cl(A)) ⊆ cl(f(A)). This relationship is fundamental in topology and can be proven using the properties of continuous functions and the definitions of closure in metric spaces. The discussion emphasizes the importance of understanding the definition of continuity and the properties associated with it to construct a valid proof.

PREREQUISITES
  • Understanding of metric spaces and their properties
  • Familiarity with the concept of closure in topology
  • Knowledge of continuous functions and their definitions
  • Basic proof techniques in mathematical analysis
NEXT STEPS
  • Study the definition of continuity in metric spaces
  • Explore the properties of closure in topological spaces
  • Learn about theorems related to continuous functions and their implications
  • Practice constructing proofs involving continuity and closure
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Mathematicians, students of topology, and anyone interested in understanding the properties of continuous functions in metric spaces.

Majrou
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Hi,
can anyone help me ?

Given Topological Spaces (metric spaces) (X, d1) and (Y,d2), show that a function f: X -> Y is continuous if and only if f(cl of A) is a subset of cl of f(A) for all A subset X1.

How can i proof this ?

Thank you!
 
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What is your definition of continuous?? What properties did you see already about continuity??

What did you try already to solve this problem??
 

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