Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3?

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The set S = {a0 + a1x + a2x2 + a3x3 | a0a3 - a1a2 = 0} is not a subspace of P3 because it fails to satisfy the closure properties required for a subspace. Specifically, while the zero polynomial is included, the addition of two polynomials from S does not guarantee that the result remains in S. The necessary conditions to verify include checking if the sum of any two polynomials in S remains in S and if scalar multiplication of a polynomial in S also results in a polynomial in S.

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Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?
 
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dmitriylm said:

Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?

Let's call your set as described above S. There are three things you need to verify to say that S is a subspace of P3:
  1. The zero polynomial is in S.
  2. If p1 and p2 are any two polynomials in S, then p1 + p2 is in S.
  3. If c is any real constant and p1 is in S, the cp1 is also in S.
 
Do I need to do anything with the conditions a0a3 – a1a2 = 0?
 
Absolutely! That equation describes the elements of your set.
 
How do I derive the elements of my set from the equation?

If I select a0=2, a1=3, a2=4, and a3=6, then these numbers meet the requirements of the equation.

Similarly, a0=-2, a1=-3, a2=-4 and a3=-6 would as well. Where do I go from there?
 
Last edited:
Unless the set is not a subspace and you can find some functions in the set that don't satisfy the subspace requirements, you won't be able to pick specific numbers for the coefficients.

Let p1(x) = a0 + a1x + a2x2 + a3x3 and p2(x) = b0 + b1x + b2x2 + b3x3, where both functions are in your set.

Is p1(x) + p2(x) also in the set?
Is k*p1(x) in the set for any constant k?
 
Thanks a lot for the help!
 
Mark44 said:
Let's call your set as described above S. There are three things you need to verify to say that S is a subspace of P3:
  1. The zero polynomial is in S.
  2. If p1 and p2 are any two polynomials in S, then p1 + p2 is in S.
  3. If c is any real constant and p1 is in S, the cp1 is also in S.

He doesn't need to show (1); this follows directly from (3).
 
The list can be shortened even more. All you really need to show is that cp1 + p2 is in the set for any constant c and any functions p1 and p2 in the set.
 
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dmitriylm said:

Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?

I think that it might just be the polynomial thing that is causing you troubles; is that accurate? If it is, could you prove that a set of vectors in R^n is a subspace of R^n. That is, what if I asked this:

Is {(a_0),(a_1),(a_2),(a_3) | a0a3 - a1a2 = 0} a subspace of R^4, could you solve it? If so, you might want to prove (or disprove) that this is a subspace of R^4, then you can literally just take your proof and translate it to P^3. Do you understand what I am saying? I'm saying that R^4 and P^3 are essentialy the same (that is, they are isomorphic.) You can't prove it in R^4 and turn this in, but you can use it to get some insights.
 

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