Is \alpha in LK determined by polynomials and elements from subfields L and K?

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SUMMARY

The discussion confirms that if L and K are subfields of M, then their composite LK is indeed the smallest subfield of M that contains both L and K. It establishes that an element α is in LK if and only if there exist positive integers n and m, polynomials f(x₁, x₂, ..., xₙ) in L[x₁, ..., xₙ] and g(x₁, x₂, ..., xₘ) in L[x₁, ..., xₘ], along with elements a₁, ..., aₙ in K and b₁, ..., bₘ in K, such that α = f(a₁, ..., aₙ) / g(b₁, ..., bₘ). This conclusion is based on the algebraic nature of α over the fields L and K.

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winter85
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Good day,

I just need someone to tell me if this is correct. If L and K are subfields of M, their composite LK is the smallest subfield of M that contains both L and K.

is this correct [tex]\alpha \in LK[/tex] if and only if there are positive integers n and m, polynomials [tex]f(x_1,x_2,...,x_n) \in L[x_1,...,x_n][/tex] and [tex]g(x_1,x_2,...,x_m) \in L[x_1,...,x_m][/tex], and elements [tex]a_1,...,a_n, b_1,...,b_m \in K[/tex] such that [tex]\alpha = \frac{f(a_1,...,a_n)}{g(b_1,...,b_m)}[/tex] ?

Thanks.
 
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Looks right, since ##\alpha## is algebraic over ##L## and ##K##, so any quotient of such numbers will do.
 

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