Is an adiabatic process isothermal also?

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Discussion Overview

The discussion centers around the relationship between adiabatic processes and isothermal processes in thermodynamics. Participants explore whether an adiabatic process must necessarily involve a change in temperature and provide examples to illustrate their points.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants assert that an adiabatic process involves a change in temperature due to the lack of heat exchange, citing that work done by the system affects its internal energy and temperature.
  • Others argue that adiabatic processes can be isothermal under specific conditions, such as adiabatic expansion into a vacuum for ideal gases, where no work is done.
  • Further contributions suggest that there are various scenarios, including electrical work and phase changes, where adiabatic processes can occur without a temperature change, emphasizing the complexity of the topic.
  • One participant acknowledges a lack of familiarity with non-equilibrium work modes, indicating that their understanding was initially based on conventional processes.

Areas of Agreement / Disagreement

Participants express disagreement regarding whether adiabatic processes must involve a temperature change, with multiple competing views presented. The discussion remains unresolved as no consensus is reached.

Contextual Notes

Participants highlight the importance of not generalizing from specific cases where temperature changes occur, indicating that assumptions about adiabatic processes may depend on the specific conditions and definitions used.

Sunny Kumar
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Is an adiabatic process isothermal also?

Can anyone please tell me if it is necessary for an adiabatic process to be isothermal? Please explain with example.
 
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No! An adiabatic process necessarily involves a change in temperature!
An adiabatic process is one in which there is no exchange of heat between the system and the surroundings (Q = 0). This implies that whatever work that is done by the system (eg a gas) or done on the system would cause a change in the internal energy and hence temperature of the system.

For instance, when a gas undergoes an adiabatic expansion, the work done by the gas has to come from the internal energy of the gas, since there is no heat transfer. Thus, the temperature of the gas falls. This is the reason why the adiabatic curve is steeper than the isotherms.
 


Fightfish said:
No! An adiabatic process necessarily involves a change in temperature!

Wrong. "Adiabatic" only means that there is no heat transfer to or from the system. Adiabatic expansion into a vacuum, for example, is isothermal for ideal gases.
 


Mapes said:
Wrong. "Adiabatic" only means that there is no heat transfer to or from the system. Adiabatic expansion into a vacuum, for example, is isothermal for ideal gases.
Ok...except for this special case where there is no resistance to expansion and no work is done :p
 


Fightfish said:
Ok...except for this special case where there is no resistance to expansion and no work is done :p

Or for processes where electrical work is done and an equal amount of P-V work extracted, or for phase changes that are achieved through hydrostatic pressure, or for multiple gases mixing... There's a universe of possible processes that are adiabatic and isothermal. It's important not to generalize from cases where the temperature does change.
 


Mapes said:
Or for processes where electrical work is done and an equal amount of P-V work extracted, or for phase changes that are achieved through hydrostatic pressure, or for multiple gases mixing... There's a universe of possible processes that are adiabatic and isothermal. It's important not to generalize from cases where the temperature does change.
Apologies. My prior exposure to thermodynamics did not cover nonequilibrium work modes, but only conventional expansion and contraction processes, thus my first instinct in thinking in that mode.
 

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