Is an Inductor Consuming or Delivering Reactive Power?

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SUMMARY

The discussion centers on the concept of reactive power in inductors within RL circuits. It clarifies that inductors do not consume reactive power; instead, they store energy in their magnetic fields and release it in a different phase. The transient state arises when the circuit is not at equilibrium, leading to a phase shift between voltage and current. The conversation emphasizes the importance of understanding these dynamics to distinguish between consuming and delivering reactive power.

PREREQUISITES
  • Understanding of RL circuits and their components
  • Knowledge of phase angles in AC circuits
  • Familiarity with differential equations related to electrical circuits
  • Basic concepts of reactive power and energy storage in inductors
NEXT STEPS
  • Study the behavior of RL circuits under different initial conditions
  • Learn about the mathematical modeling of reactive power in AC circuits
  • Explore the concept of power factor and its implications in electrical systems
  • Investigate the role of synchronous machines in power networks
USEFUL FOR

Electrical engineers, students studying power systems, and professionals involved in circuit design and analysis will benefit from this discussion.

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Trying to understand the power network and synchronous machines, led me to the fact that I am not sure about the basics.

The terms the generator is delivering or consuming reacting power made me halt.


So I went back to my old course(which I allegedly passed) where the reactive power is addressed. I couldn't understand that back then(1 year) because I barley handled the phase angle, let alone problems of reactive power and its true meaning.



Consider a RL circuit. Plain. (or real inductor).



Solving the differential equation(which I didn't know how to do back then) gives me this:

for u(t)=U_m\cdot sin(\omega t+\theta _u)

I get that the current is changing like:

i(t)=I_m\cdot sin(\omega t+\theta _u-\phi _L)-I_ m\cdot sin(\theta _u -\phi _L)\cdot e^{-\frac{R}{L}t}

Lets discuss this:

We have 2 components. First component represents a steady-state current.

Second component represents a transient-state which slowly fades.


My question here is:


Do we say for an inductor, that is consuming reactive power?

If we make the angle of the voltage source u(t) such that it cancels the transient-state, did we in fact, "configured" that voltage source, to give OUT reactive power, and give it out just SO much that it cancels the "needs" of that inductor?


These are the questions for now, tons of other are awaiting, but first I have to make a clear distinction between giving out and consuming reactive power.
 
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I usually forward people to this. I think it describes the differences well.
http://www.allaboutcircuits.com/vol_2/chpt_11/2.html
 
Do we say for an inductor, that is consuming reactive power?

It's all a agreement how we call that.. consuming means that the current is lagging. There is no power consumption - the reactive power is stored in inductiors magnetic field (stored in one period and moved out in another period).

If we make the angle of the voltage source u(t) such that it cancels the transient-state, did we in fact, "configured" that voltage source, to give OUT reactive power, and give it out just SO much that it cancels the "needs" of that inductor?

First of all.. where from comes the transient state ? Tranient occurs when You start from "u(t=0) not eq amplitude". Why ? When U is at it's peak I is equal to 0 (90deg phase shift, obvious). But what about reactive power ? When "q(t=0) is eq to 0" the circuit starts with no transients. At point (t=0"-") the total energy stored in inductor is zero, and there can't be a discontinous energy change.
 
es1 said:
I usually forward people to this. I think it describes the differences well.
http://www.allaboutcircuits.com/vol_2/chpt_11/2.html

Thank you for your link. Very useful.
 

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