Is an unspecified matrix invertible?

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SUMMARY

The linear operator T defined on C3, with T_{\epsilon1}=(1,0,i), T_{\epsilon2}=(0,1,1), and T_{\epsilon3}=(i,1,0), is not invertible. This conclusion arises from the observation that T maps a three-dimensional space to a two-dimensional space, indicating that T is not onto and therefore not nonsingular. The discussion emphasizes the need to demonstrate that T is either non-singular or onto to establish its invertibility.

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Homework Statement


Let T be the unique linear operator on C3 for which [tex]T_{\epsilon1}=(1,0,i), T_{\epsilon2}=(0,1,1), T_{\epsilon3}=(i,1,0).[/tex]
Is T invertible?
2. Homework Equations
If we show T is non singular or T is onto, then this would imply T is invertible.

The Attempt at a Solution


I don't really know where to start, I thought about trying to brute force solve the matrix T but I am quite sure there is a more elegant way and hoping someone can give me a kick in that direction.
 
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Assuming the scalars for this vector space are the complex numbers, I think [itex]Te_1[/itex] is a linear combination of [itex]Te_2[/itex] and [itex]Te_3[/itex]. If that's correct then you can show that T maps a 3-D space to a 2-D space.
 

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