Karma
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sec(pi)=2/2x+1
-1=2/2x+1
-2x-1=2
-2x=3
x=-3/2
is this correct?
-1=2/2x+1
-2x-1=2
-2x=3
x=-3/2
is this correct?
The discussion revolves around the equation involving the secant function, specifically sec(pi(2x+1)) = 2, and its implications for finding values of x. Participants are exploring the relationship between secant and cosine in this context.
The discussion is ongoing, with participants clarifying the equation and its interpretation. There is a focus on understanding the implications of the secant function and its relationship to cosine, but no consensus has been reached on the interpretation of the original problem.
There is some confusion regarding the notation used in the equation, particularly the placement of parentheses, which may affect the interpretation of the problem. Participants are also considering how to approach the problem without a clear resolution yet.
Karma said:sec(pi(2x+1))= 2 is what i mean.