Is Cos(pi(2x+1)) the Key to Simplifying the Search for x Values?

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Homework Help Overview

The discussion revolves around the equation involving the secant function, specifically sec(pi(2x+1)) = 2, and its implications for finding values of x. Participants are exploring the relationship between secant and cosine in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the original equation and its structure, with some questioning the notation and the number of parentheses used. There is also a suggestion to explore the cosine function in relation to the secant equation to simplify the search for x values.

Discussion Status

The discussion is ongoing, with participants clarifying the equation and its interpretation. There is a focus on understanding the implications of the secant function and its relationship to cosine, but no consensus has been reached on the interpretation of the original problem.

Contextual Notes

There is some confusion regarding the notation used in the equation, particularly the placement of parentheses, which may affect the interpretation of the problem. Participants are also considering how to approach the problem without a clear resolution yet.

Karma
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sec(pi)=2/2x+1
-1=2/2x+1
-2x-1=2
-2x=3
x=-3/2

is this correct?
 
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is the original supposed to be sec(pi)(2x+1) = 2?
 
sec(pi(2x+1)=2

the original
 
That doesn't make any sense. You have two "(" and only one ")".
The whole question is whether you mean sec(pi(2x+1))= 2 or sec(pi(2x)+ 1= 2 and you still haven't answered that.
 
sec(pi(2x+1))= 2 is what i mean.
 
Karma said:
sec(pi(2x+1))= 2 is what i mean.

So cos(pi(2x+1)) = ? Does that suggest an easier way to search for the values of x?
 

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