Is Cu(ClO4)2 Omitted in Net Ionic Equations?

[ChrisEffinSmi]

I've been struggling with this for a while now. Cu(ClO4)2 is soluble so it should drop from both sides of the net ionic equation, right? Leaving only H20. Am I missing something?

http://usera.imagecave.com/hotrod73dart/question/netionic.JPG

 

[Borek]

Cu(OH)₂ is insoluble. There is a reason why it is marked with (s).

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methods

 

[Bohrok]

But if you have something solid like Cu(OH)₂, you need to leave it in the equation, regardless of whether any of its ions (such as Cu²⁺) have separated on the other side of the equation.