Is energy conserved in this case?

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SUMMARY

The discussion centers on the conservation of energy in the context of a figure skater's rotational dynamics. Initially, the skater has a moment of inertia that allows her to rotate at 4 rad/s, which increases to 12 rad/s after reducing her moment of inertia by a factor of 3. While angular momentum is conserved, the analysis reveals that mechanical energy is not conserved due to the work done by the skater in pulling her arms in, thus transforming chemical energy into mechanical energy.

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  • Understanding of angular momentum conservation principles
  • Familiarity with rotational energy calculations using the formula R.E. = 1/2Iw²
  • Knowledge of moment of inertia and its impact on rotational motion
  • Basic concepts of energy transformation in physical systems
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Stereo_Chemist
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I recently had a question presented to me, and I am wondering if I got it right.

The question stated that a figure skater with a moment of inertia was rotating at an angular speed of 4 rad/s. Then the figure skater reduced her moment of inertia by bringing her arms in, and her speed increased to 12 rad/s. How much did her moment of inertia increase by.

For this part I know that angular momentum is conserved, so if the angular speed increased by a factor of 3, her moment of inertia must decrease by a factor of 3 also.

The next question then asked if energy was conserved in this case.

I figured that the only type of energy in this case was rotational energy and there is no translational energy, so you could simply use the formula

R.E. = 1/2Iw^2

So if you plug in the initial moment of inertia and angular speed and then the final one, you will get two different values, so energy is not conserved, correct?
 
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Correct. Mechanical energy is not conserved. The skater has to do work to pull in her arms; she adds mechanical energy. (Of course total energy is conserved. She transformed chemical energy into mechanical energy.)
 

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