Is f(q1, p1) an Integral of Motion in This Hamiltonian System?

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SUMMARY

In the discussion regarding the Hamiltonian system, it is established that if the Hamiltonian H depends on q1 and p1 only through a function f(q1, p1), then f(q1, p1) is indeed an integral of motion. The proof hinges on the commutation relations, specifically that [q1, H] = [p1, H] = 0, indicating that both q1 and p1 are integrals of motion. The final step involves computing the Poisson bracket between f and H to solidify the conclusion that f(q1, p1) retains the property of being an integral of motion.

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  • Understanding of Hamiltonian mechanics
  • Familiarity with Poisson brackets
  • Knowledge of integrals of motion in classical mechanics
  • Basic grasp of commutation relations
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This discussion is beneficial for physicists, particularly those specializing in classical mechanics and Hamiltonian systems, as well as students seeking to deepen their understanding of integrals of motion and Poisson brackets.

Oreith
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Missing homework template due to being originally posted in another forum.
I am stuck on a proof. I need to show that if a Hamiltonian only depends on q1 and p1 though a function f(q_1,p_1), that is; H(f(q_1, p_1), q_2, p_2, q_3, p_3, ... q_n, p_n) then f(q_1, p_1) is an integral of motion.

My attempt at a solution is as rather simplistic but I'm stuck making the final jump. Since the Hamiltonian is not directly a function of q1 and p1 it must commute;

[q_1, H] = [p_1, H] = 0

so q1 and p1 are integrals of motion. How do i then say that a function of those two variables is also an integral of motion, it feels intuitive but I cannot figure out how to write it down.
 
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Have you tried simply computing the Poisson bracket between ##f## and ##H##?
 
I have now, thanks =)
 

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