Is f(x) a closed interval if f is continuous and onto on a bounded interval?

Click For Summary

Homework Help Overview

The discussion revolves around the properties of continuous functions, specifically whether the image of a continuous and onto function defined on a bounded interval must also be a closed interval. Participants explore the implications of continuity on closed and open intervals and question the existence of certain mappings.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss theorems related to continuous functions and their images, questioning the nature of mappings from closed to open intervals and vice versa. They explore examples of continuous functions and their ranges, particularly focusing on whether certain mappings can exist.

Discussion Status

The discussion is active, with participants providing insights into theorems and questioning the existence of specific functions. Some participants express uncertainty in finding examples, while others suggest methods for constructing such functions, indicating a productive exploration of the topic.

Contextual Notes

There is mention of the constraints of the problem, particularly regarding the definitions of closed and open intervals and the requirement for functions to be onto. Participants are also grappling with the implications of these definitions in the context of continuous functions.

rapple
Messages
25
Reaction score
0
1.Is it true that if f is continuous onto function on a closed interval then f(x) must also be a closed interval. How about the other way around. f is continuous and onto on a open bounded interval and f(x) is a closed interval

Homework Equations


f:[0,1]-->(0,1)
f:(0,1)-->[0,1]


The Attempt at a Solution


There is a theorem that says that if f is continuous on a closed and bounded interval then set of f(x) is a closed and bounded interval.
 
Physics news on Phys.org
True, that is a theorem. f continuous on a closed interval then the image of f is a closed interval. If f is continuous on an open interval then the range can be closed, open or neither. Can you find an example of each?
 
Dick said:
True, that is a theorem. f continuous on a closed interval then the image of f is a closed interval. If f is continuous on an open interval then the range can be closed, open or neither. Can you find an example of each?

Does this mean that f:[0,1]-->(0,1) does not exist. If both are closed intervals there are several examples, including the trivial f(x)=x

I don't have an example for continuous onto f:(0,1)-->[0,1]
 
Yes, there is no continuous function f mapping [0,1]->(0,1). You cited the theorem. For mapping (0,1) into [0,1], can't you think of a function where f(0)=1/2, f(1/3)=1, f(2/3)=0 and f(1)=1/2? Surely you can draw one.
 
Dick said:
Yes, there is no continuous function f mapping [0,1]->(0,1). You cited the theorem. For mapping (0,1) into [0,1], can't you think of a function where f(0)=1/2, f(1/3)=1, f(2/3)=0 and f(1)=1/2? Surely you can draw one.

It has to be an onto function. I am not aware of one as you have described.
 
Onto what? It's certainly onto [0,1].
 
Yes. But I don't have an example as you have described. Sorry. I am always bad with examples.
 
Can't you linearly interpolate between the values I gave? You could also fit it to a polynomial. You could scale a sine function. Any number of things you could do to get an explicit example. You did sketch one, right? That's all I care about.
 
Dick said:
Can't you linearly interpolate between the values I gave? You could also fit it to a polynomial. You could scale a sine function. Any number of things you could do to get an explicit example. You did sketch one, right? That's all I care about.

sin(4x) works

Thx
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
1
Views
2K
Replies
11
Views
2K