Is F(x, y, z) a Conservative Vector Field?

[duki]

Homework Statement

Determine if the following is conservative.
$$F(x, y, z) = (4xy + z^2)i + (2x^2 + 6yz)j + (2xz)k$$

Homework Equations

The Attempt at a Solution

I'm not entirely sure I'm doing this correctly. I've taken the partial of M with respect to y and got 4x. I then took the partial of N with respect to x and got 4x. My question is how do I check P (2xz) ? Does it matter if I take the partial with respect to x or y, or will both work for the test?

 

[dx]

What test exactly are you doing? To show that F is conservative, you just have to show that ∇ x F = 0.

 

[duki]

I'm doing the test that says something like... if all of the partials are equal then it is conservative. Is there an easier way?

 

[dx]

No there's no test like that. The definition of conservative vector field is this: F is conservative is there is a scalar field φ such that F = ∇φ. This is equivalent to showing that ∇ x F = 0 (unless we're working on regions that are not simply connected, but let's not worry about that now).

 

[diazona]

I'm doing the test that says something like... if all of the partials are equal then it is conservative. Is there an easier way?

That is sort of like taking the curl:
$$\vec{\nabla}\times\vec{F} =<br /> \left(\frac{\partial F_z}{\partial y} - \frac{\partial F_y}{\partial z}\right)\hat{x}<br /> +\left(\frac{\partial F_x}{\partial z} - \frac{\partial F_z}{\partial x}\right)\hat{y}<br /> +\left(\frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y}\right)\hat{z}$$
In your first post, you basically described computing the first of the three components and verifying that it's zero (because each of the two derivatives is 4x, so they're equal). You can just do the same thing for the other two components of the curl.

 

[duki]

That is sort of like taking the curl:
$$\vec{\nabla}\times\vec{F} =<br /> \left(\frac{\partial F_z}{\partial y} - \frac{\partial F_y}{\partial z}\right)\hat{x}<br /> +\left(\frac{\partial F_x}{\partial z} - \frac{\partial F_z}{\partial x}\right)\hat{y}<br /> +\left(\frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y}\right)\hat{z}$$
In your first post, you basically described computing the first of the three components and verifying that it's zero (because each of the two derivatives is 4x, so they're equal). You can just do the same thing for the other two components of the curl.

Ok, this is what I'm trying to do. I'm not sure about the tests though. Can I stop as soon as one of them doesn't match? Also, does it matter if I take P with respect to x or P with respect to y?

The test I've been doing is if My = Nx, Mz = Px, Nz = Py then the field is conservative and I can continue to find the potential function.

 

[dx]

To show that F is conservative, you have to check all three components of the curl, i.e. you have to show that

∂_yP = ∂_zN

∂_zM = ∂_xP

∂_xN = ∂_yM

(I'm assuming you're using the notation M = F_x, N = F_y, P = F_z)

Of course, if one of them doesn't match, that's enough to show it's not conservative.

 

[duki]

ahhh i c. Thanks