Is it possible to factor on a Ti-83 Calcultor?

[MoreZitiPlease]

Homework Statement

Like if I wanted to factor x^2 + 24x +80 {EXAMPLE}
Is this possible?

Homework Equations

The Attempt at a Solution

 

[Mindscrape]

This is definitely possible. What are some factors of 80 that will add to 24?

Edit:
Oh whoops I just saw that you were looking for factoring on Ti-83 calculator. But why would you want to do that when you can factor by hand? I don't think you can do it anyway.

 

[MoreZitiPlease]

because midterms are tomorrow and I am weak on factoring :)

 

[rocomath]

Ok calculators suck. If you can't find factors to factor your function, then just use the quadratic formula.

 

[Mindscrape]

You mean to say that you want to cheat, yourself and your teacher? Obviously the idea is to test your ability to factor, not your calculator's ability. Nothing cures the problem like a healthy dose of practice.

 

[AFG34]

well practicing will make you more comfortable with them. Read up on the factor theorem also.

if my casio991MS can factor, the Ti-83 will probably be able to also.

 

[CompuChip]

You can just solve x^2 + 24x + 80 = 0 and once you have the solutions, use those to factor :)

E.g. quadratic formula gives
x_\pm = \frac{ - 24 \pm \sqrt{24^2 - 4 \cdot 80}}{2} = - 12 \pm 8 = -20, -4
So it factors as
(x + 20)(x + 4)

If you insist on doing it with the GC, you could use the equation solver...
$$ [0 (Solver)]

Enter the equation
(X^2 + 24X + 80)
and solve it (press Enter, Alpha + Enter (Solve))
You will get a solution, e.g. X = -4
Then divide out this solution from the original equation, so go back and enter
(X^2 + 24X + 80)/(X + 4)
(note the sign) -- now solve again and it will give you the other one.
Then you have again X = -4, X = -20, so it factors as
(X + 4)(X + 20)

 

[thharrimw]

start a new program and put these lines as your program
:Disp "Ax^2+BX+C"
:prompt A,B,C
:(B^2-(4AC))^(1/2)->D
:-B+D->E
:-B-D->F
:2A->A
:Disp "roots=",E/A,F/A
that will do the quadratic formula

 

[disregardthat]

What is this notation x_\pm, what does it mean?

 

[CompuChip]

It means there are two solutions, which we denote by x_+ and x_- (might as well have called them x_1 and x_2, or x and y.
The first one is
x_1 = x_+ = \frac{ - b + \sqrt{D}}{2} (*)
and the other is
x_2 = x_- = \frac{ - b - \sqrt{D}}{2} (**)
where D is the usual discriminant
D = b^2 - 4 a c.

It is common to write the formulas (*) and (**) together in one line as
x_{1,2} = x_\pm = \frac{ - b \pm \sqrt{D}}{2}
where we mean: pick either the plus or the minus sign throughout.

The same notation also occurs in e.g.
\sqrt{4} = \pm 2
which means that +2 and -2 are both solutions, so shorthand for
\sqrt{4} = 2 \text{ or } -2.

(Aside, we also have an opposite symbol, which can be used in for example
"If x = \pm 1 then -2x = \mp 2"
which means both "if x then -2x = -2" and "if x = -2 then -2x = +2" simultaneously).

 

[Gear300]

TI-83...probably not. But you could graph the function and find the roots, which comes off pretty easy.

 

[neofreakx2]

Of course there's a way to do it. Like someone said earlier, you can just take the zeroes of the function and place the opposite of it in the "factored form". Just use a program to do the quadratic and multiply the answer by -1, and display "(X",D,")", and the same for the second value.

:Prompt A
:Prompt B
:Prompt C
sqrt. (B^2-4AC)->C
-B+C->D
-B-C->E
2A->A
-1D/A->D
-1E/A->E
D>Frac->D
E>Frac->E
:Disp "(X",D,")(X",E,")"

I just came up with this off the top of my head, so I haven't tested it. It might take a little tinkering, most likely in the display command (I can never seem to get those to work right when I'm using variables). It should work though. If it remains in decimal form, that means it can't be factored rationally. Otherwise, it's pretty self-explanitory.

 

[thharrimw]

Of course there's a way to do it. Like someone said earlier, you can just take the zeroes of the function and place the opposite of it in the "factored form". Just use a program to do the quadratic and multiply the answer by -1, and display "(X",D,")", and the same for the second value.

:Prompt A
:Prompt B
:Prompt C
sqrt. (B^2-4AC)->C
-B+C->D
-B-C->E
2A->A
-1D/A->D
-1E/A->E
D>Frac->D
E>Frac->E
:Disp "(X",D,")(X",E,")"

I just came up with this off the top of my head, so I haven't tested it. It might take a little tinkering, most likely in the display command (I can never seem to get those to work right when I'm using variables). It should work though. If it remains in decimal form, that means it can't be factored rationally. Otherwise, it's pretty self-explanitory.

if you use this program;
:Prompt A
:Prompt B
:Prompt C
sqrt. (B^2-4AC)->C
-B+C->D
-B-C->E
2A->A
-1D/A->D
-1E/A->E
D>Frac->D
E>Frac->E
:Disp "(X",D,")(X",E,")"
you will get a incorrect answer use this
Set Mode To A+Bi
:Prompt A,B,C
:sqrt. (B^2-4AC)->C
:-B+C->D
:-B-C->E
:2A->A
:D/A->D
:E/A->E
:Disp "Roots",D>Frac,E>Frac

 

[||spoon||]

why not just graph the function and find the x-intercepts...?

 

[||spoon||]

by graph i meant sketch (on calculator) sorry for any misunderstandings caused. Also i agree with the other guys... Just do it by hand!

 

[neofreakx2]

Because for some reason, most people who aren't in a major involving math are too lazy. If you just have to put the numbers into the calculator, you don't even have to bother putting the graph function in and finding the zeroes.