Is It Possible to Solve This Diffusion Equation via Separation of Variables?

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Homework Help Overview

The discussion revolves around a diffusion equation in fluid mechanics, specifically the equation $$\frac{\partial U}{\partial t}=\nu \frac{\partial^{2} U}{\partial y^{2}}$$ with specified boundary and initial conditions. Participants are exploring the feasibility of solving this equation using the separation of variables method.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply separation of variables but expresses uncertainty about its effectiveness due to the boundary conditions. They question whether an analytic solution is achievable through this method, especially given the behavior of the function as it approaches zero.
  • Another participant requests to see the separation of variables process and the resulting differential equations.
  • There is mention of using Laplace transforms as an alternative approach, with a suggestion that separation of variables may lead to incorrect functions.

Discussion Status

The discussion is ongoing, with participants exploring different methods to tackle the problem. Some guidance has been offered regarding the use of Laplace transforms, indicating a potential direction for further investigation. However, there is no explicit consensus on the best approach yet.

Contextual Notes

Participants are grappling with the implications of the boundary conditions and the nature of the solutions that can be derived from the separation of variables method. The original poster notes the challenge posed by the first boundary condition and the requirement for the solution to converge to zero.

Remixex
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Homework Statement


$$\frac{\partial U}{\partial t}=\nu \frac{\partial^{2} U}{\partial y^{2}}$$
$$U(0,t)=U_0 \quad for \quad t>0$$
$$U(y,0)=0 \quad for \quad y>0$$
$$U(y,t) \rightarrow {0} \quad \forall t \quad and \quad y \rightarrow \infty$$

Homework Equations


This is a diffusion problem on fluid mechanics, but it's more of a math problem so i posted it here.

The Attempt at a Solution


I'm trying to solve this via separation of variables (the textbook uses a "similarity" method I've never seen before, and concludes the function U must be erf) is it even possible to reach an analytic result via SV?
The first boundary condition is what gets me, I tried
$$U_{0} e^{{k^{2}t}} e^{{-\frac{k}{\sqrt{\nu}}y}}$$
But it clearly doesn't work for any boundary condition except the last.
I don't think sinusoidal is the answer here either because it must eventually converge to zero, for every t.
Is there really no analytic answer?
 
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Please show your separation of variables and the resulting differential equations.
 
Remixex said:

Homework Statement


$$\frac{\partial U}{\partial t}=\nu \frac{\partial^{2} U}{\partial y^{2}}$$
$$U(0,t)=U_0 \quad for \quad t>0$$
$$U(y,0)=0 \quad for \quad y>0$$
$$U(y,t) \rightarrow {0} \quad \forall t \quad and \quad y \rightarrow \infty$$

Homework Equations


This is a diffusion problem on fluid mechanics, but it's more of a math problem so i posted it here.

The Attempt at a Solution


I'm trying to solve this via separation of variables (the textbook uses a "similarity" method I've never seen before, and concludes the function U must be erf) is it even possible to reach an analytic result via SV?
The first boundary condition is what gets me, I tried
$$U_{0} e^{{k^{2}t}} e^{{-\frac{k}{\sqrt{\nu}}y}}$$
But it clearly doesn't work for any boundary condition except the last.
I don't think sinusoidal is the answer here either because it must eventually converge to zero, for every t.
Is there really no analytic answer?

Use Laplace transforms with respect to ##t##. Let
$$W(y,s) = \int_0^{\infty} e^{-st} U(y,t) \, dt $$
be the Laplace transform. Then, using standard properties of Laplace transforms, we get the DE
$$\nu W_{yy}(y,s) = s W(y,s) - U(y,0) = s W(y,s),$$
where ##W_{yy} = \partial^2 W / \partial y^2##.
Also: ##U(0,t) = U_0## implies that
$$W(0,s) = \frac{U_0}{s} $$
Finally, the initial value theorem requires that ##\lim_{s \to \infty} s W(y,s) = 0## for ##y > 0##.

These are enough to determine ##W(y,s)##. Then it is just a matter of taking the inverse Laplace transform of ##W(y,s)## to get ##U(y,t)##.

Separation of variables will never work in this example, simply because it leads to the wrong kind of function.
 
Last edited:
Ray Vickson said:
Separation of variables will never work in this example, simply because it leads to the wrong kind of function.
THANK YOU :D
 

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