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Volcano, you already asked this in post 19 and I already answered in post 20. Stop repeating yourself.
I'm not sure what you're asking here. Clearly we can perform a gedanken experiment, whether or not we can perform an actual experiment is irrelevant here.Volcano said:I am really asking, is there such an experiment?
Yes, as has been said many times in this thread a photon pair resulting from the annihilation of an electron and positron pair has a non-zero mass, but is not considered matter.Volcano said:And second question; is there something has mass but not matter, what is it?
This is entirely correct, individual photons are massless.QuantumPion said:So essentially you are saying that since an electron and a positron have mass, and they can annihilate to create two photons, those two photons have mass? I'm pretty sure this is entirely incorrect. Photons are massless.
You are correct. I was thinking only of elementary particles where elementary bosons do not take up space due to not obeying the Pauli exclusion principle.QuantumPion said:many bosons can occupy the same space. That space isn't necessarily zero. For example, a Bose-Einstein condensate of helium atoms.
If matter is anything that has mass and a hot gas has more mass than a cold gas then I don't see how you can consistently claim that a hot gas does not have more matter than a cold one.QuantumPion said:I think you are a bit confused. This is exactly what I am arguing AGAINST, and what you have been arguing in favor of until your last paragraph! I specifically stated that a hot gas does NOT have more matter then a cold gas. I stated "matter is anything that has mass".
I am using the usual definition of mass as being the invariant norm of the four-momentum, aka rest mass. I am certainly not talking about relativistic mass. The invariant rest mass of the hot gas is higher than that of the cold gas. A hot gas has more energy in its rest frame, it has more inertia as measured in its rest frame, and according to GR it has more gravity.QuantumPion said:When you posited that a hot gas has greater "mass" then a cold gas as an example to disprove my definition, I pointed out that your argument was flawed because the "relativistic mass" of a hot gas is not the same as rest mass.
DaleSpam said:This is entirely correct, individual photons are massless.
|(.511, .511,0,0) MeV/c|/c = 0 MeV/c²
|(.511,-.511,0,0) MeV/c|/c = 0 MeV/c²
But a system of photons can have mass if the photons are not traveling in the same direction.
(.511,.511,0,0) MeV/c + (.511,-.511,0,0) MeV/c = (1.022,0,0,0) MeV/c
|(1.022,0,0,0) MeV/c|/c = 1.022 MeV/c²
In general a system of particles will have a different mass than the sum of the masses of its constituent particles.,