Is "Multiplication Commutative in Rings?

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Discussion Overview

The discussion revolves around the properties of multiplication in rings, specifically examining the commutativity of multiplication and the implications for the equation (-x) * y = x * (-y). Participants explore the proof that -1 * -1 = 1, utilizing the distributive property and properties of additive inverses.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions whether the equation (-x) * y = x * (-y) holds true for all rings, suggesting that commutativity may be necessary for the proof.
  • Another participant proposes using the distributive property to demonstrate that -1 * -1 = 1.
  • Further elaboration on the proof involves showing that (-1)(1 + (-1)) = 0 leads to the conclusion that (-1)(-1) = 1.
  • Some participants clarify that the conclusion is not merely by definition, but rather follows from the properties of additive inverses and the multiplicative identity.
  • There is a reiteration of the steps taken to arrive at the conclusion, emphasizing the additive inverse relationship between 1 and -1.

Areas of Agreement / Disagreement

Participants generally agree on the steps to prove that -1 * -1 = 1, but there is contention regarding the characterization of this conclusion as being by definition.

Contextual Notes

Some assumptions regarding the properties of rings and the definitions of additive and multiplicative identities are implicit in the discussion. The proof relies on the distributive property and the nature of additive inverses, which may not be universally accepted without further context.

1MileCrash
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Is (-x) * y = x * (-y) true for all rings?

It seems simple enough but I feel like * must be commutative when trying to prove this.
 
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Never mind, I have it.

But how can I show that -1 * -1 = 1 where 1 is the multiplicative identity?
 
Last edited:
Use the distributive property with
(-1)(1+(-1))=0
 
lurflurf said:
Use the distributive property with
(-1)(1+(-1))=0
Cool,

(-1)(1) + (-1)(-1) = 0
-1 + (-1)(-1) = 0

(-1)(-1) = 1 by definition
 
1MileCrash said:
Cool,

(-1)(1) + (-1)(-1) = 0
-1 + (-1)(-1) = 0

(-1)(-1) = 1 by definition
Not by definition.

1 + (-1) = 0 since 1 and -1 are additive inverses of each other
-1(1 + (-1)) = -1(0) = 0, since 0 times anything is 0.
-1(1) + (-1)(-1) = 0
Since -1(1) and (-1)(-1) add to zero, they are additive inverses.
We know that -1(1) = -1, since 1 is the multiplicative identity,
so -1(-1) must equal 1.
 
Mark44 said:
Not by definition.

1 + (-1) = 0 since 1 and -1 are additive inverses of each other
-1(1 + (-1)) = -1(0) = 0, since 0 times anything is 0.
-1(1) + (-1)(-1) = 0
Since -1(1) and (-1)(-1) add to zero, they are additive inverses.
We know that -1(1) = -1, since 1 is the multiplicative identity,
so -1(-1) must equal 1.

Yes, exactly.
 

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