• Math10

## Homework Statement

Solve Q'+(1/(50+t))Q=1.

None.

## The Attempt at a Solution

This is my work:
I know that the integrating factor is (1/(50+t)).
e^integral of (1/(50+t))dt=e^ln abs(50+t)=50+t
(50+t)Q'+Q=50+t
Q(50+t)=50t+t^2+C
Q=(50t+t^2+C)/(50+t)
I got Q=(50t+t^2+C)/(50+t) as the answer. Am I right?

You can check this yourself by substituting for Q and Q' in the original ODE.

## Homework Statement

Solve Q'+(1/(50+t))Q=1.

None.

## The Attempt at a Solution

This is my work:
I know that the integrating factor is (1/(50+t)).
e^integral of (1/(50+t))dt=e^ln abs(50+t)=50+t
(50+t)Q'+Q=50+t
Q(50+t)=50t+t^2+C
Q=(50t+t^2+C)/(50+t)
I got Q=(50t+t^2+C)/(50+t) as the answer. Am I right?

I concur with SteamKing's answer. You can easily check it yourself, and it would be good to develop the habit of checking on your own.

I think most of us at PF frown on abandoning a thread and then starting a new one like it was a different subject.
Yes.

Math10, do not abandon a thread, and then start a new one on the same problem.

Also, as SteamKing and Ray Vickson have pointed out, you can and should, check answers to problems like this on your own.

Okay. I won't abandon a thread again.

And I have already solved the problem.