Is My Book Correct About the Integral of e^-ax from Negative Infinity to 0?

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Homework Help Overview

The discussion revolves around the evaluation of the integral of the function e^-ax from negative infinity to zero, specifically questioning the correctness of a book's assertion regarding the equivalence of two integrals involving the absolute value of x.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the absolute value function when x is negative and its effect on the integral. There is a focus on understanding the relationship between |x| and -x in this context.

Discussion Status

The discussion is active, with participants questioning the assumptions made about the absolute value and its application in the integral. Some guidance is being provided through examples, but no consensus has been reached regarding the correctness of the book's statement.

Contextual Notes

Participants are examining the definitions and properties of absolute values in relation to negative inputs, which may influence the interpretation of the integral. There is an emphasis on clarifying these mathematical concepts rather than solving the integral itself.

leopard
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Is my book right to write

[tex]\int ^{0}_{- \infty}e^{-a|x|}dx = \int ^{0}_{- \infty}e^{ax}dx[/tex]

?

In case, why?
 
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If x is negative, what is |x|?
 
positive, but -a is still negative.
 
That was not the question. If x is negative, then |x|= -x. For x negative, -a|x|= (-a)(-x)= ax.
 
errmmm...maybe it's best to think of an example...suppose you have x=-2, what is |x|?
 
|-2| = 2
 
leopard said:
|-2| = 2

Right, and if x=-2, what is -x?
 
Should be 2. I can simply put the minus outside the brackets?
 
leopard said:
Should be 2. I can simply put the minus outside the brackets?

Well, if |x|=2 and -x=2, then surely you can say that |x|=-x?:wink:


So...what does that make -a|x|?
 

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