Is my book making an algebra error?

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SUMMARY

The discussion centers around a potential algebra error in a book's presentation of a system of equations involving time dilation, represented as τ_b and τ_a. The equations are τ_b = (1 + (Φ_b/c²))Δt, τ_a = (1 + (Φ_a/c²))Δt, and τ_b = (1 + (Φ_{b-}Φ_a/c²))τ_a. The participant expresses difficulty in transforming the equations into the book's form and questions whether the discrepancy arises from a notation error or an algebraic misunderstanding. A suggestion is made that the book may be making an approximation under the assumption that Φ_a/c² is significantly smaller than 1.

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ozone
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Not sure if this is a notation error or an algebra or if I am wrong , but my book presents a system of equations and I cannot get it into the form which it is presented

[itex]\tau _b = \left(1 + \frac{\Phi _b}{c^2}\right)\text{ }\text{$\Delta $t}[/itex]

[itex]\tau _a = \left(1 + \frac{\Phi _a}{c^2}\right)\text{ }\text{$\Delta $t}[/itex]

[itex]\tau _b = \left(1 + \frac{\Phi _{b-}\Phi _a}{c^2}\right)\text{ }\tau _a[/itex]

Just wondering if I am missing something obvious here or if they are performing black magic. I tried subbing in for delta t and then doing long division but my answer was slightly different from their form.
 
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ozone said:
Not sure if this is a notation error or an algebra or if I am wrong , but my book presents a system of equations and I cannot get it into the form which it is presented

[itex]\tau _b = \left(1 + \frac{\Phi _b}{c^2}\right)\text{ }\text{$\Delta $t}[/itex]

[itex]\tau _a = \left(1 + \frac{\Phi _a}{c^2}\right)\text{ }\text{$\Delta $t}[/itex]

[itex]\tau _b = \left(1 + \frac{\Phi _{b-}\Phi _a}{c^2}\right)\text{ }\tau _a[/itex]

Just wondering if I am missing something obvious here or if they are performing black magic. I tried subbing in for delta t and then doing long division but my answer was slightly different from their form.

Could it be that they are making an approximation under the assumption that ##\frac{\Phi_a}{c^2}## is much smaller than 1?
 
Ahh I suppose that you are probably right.. thank you.
 

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