Is My Calculation for Astronaut's Centripetal Acceleration Correct?

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SUMMARY

The discussion centers on calculating the required rotation rate for an astronaut to experience a centripetal acceleration of 3g while in circular motion with a radius of 9.45 meters. The initial equation used was ac = v²/r, leading to a calculated velocity of 1.76 m/s. However, upon substituting this value into the period formula T = 2πr/v, the resulting rotation rate of 33.73 rev/s was deemed excessively high, indicating a potential error in the velocity calculation or unit conversion.

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Homework Statement


Determine the rotation rate, in rev/s, required to give an astronaut a centripetal acc of 3g while in circular motion with radius 9.45 m.



Homework Equations


ac=v^2/r
i did 3g=v^2/9.45 and got 1.76
then i used T=2pie(r)/v, put in T=2pie(9.45)/1.76



The Attempt at a Solution


with doing what i did above i got 33.73. this doesn't seem right. 33 rev/s? that would be fast!
 
Physics news on Phys.org
Double check your calculation for the velocity, it can't be right.

Also, make sure you check that your units work out in your calculations. If they don't come out to what you want, you've made a mistake somewhere.
 

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