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**1. An athlete whirls a 7.48 kg hammer tied to**

the end of a 1.4 m chain in a horizontal circle.

The hammer moves at the rate of 1.76 rev/s.

What is the centripetal acceleration of the

hammer? Assume his arm length is included

in the length given for the chain.

Answer in units of m/s

the end of a 1.4 m chain in a horizontal circle.

The hammer moves at the rate of 1.76 rev/s.

What is the centripetal acceleration of the

hammer? Assume his arm length is included

in the length given for the chain.

Answer in units of m/s

**2. Equations I am pretty sure I need are**

v = 2∏r/T

and

a

not sure if I need any others.

v = 2∏r/T

and

a

_{c}= v^{2}/rnot sure if I need any others.

**3. I tried finding v first, and I assumed the 1.76 rev/s was T, so I did 2*∏*1.4(about 8.80) and divided it by 1.76, getting about 4.99 m/s**

and I plugged it in to the a

So I squared the 4.99, getting about 24.98, and dividng it by 1.4, which gets me about 17.843.

But that answer is wrong.

I don't know what the answer is.

I feel like what I am doing wrong is the 1.76 rev/s is not T, or it is, but I have to change it so it's in like m/s or something like that. If that's the case, then I need help finding that because I have no idea how to do that.

Thank you for any help!

and I plugged it in to the a

_{c}equation.So I squared the 4.99, getting about 24.98, and dividng it by 1.4, which gets me about 17.843.

But that answer is wrong.

I don't know what the answer is.

I feel like what I am doing wrong is the 1.76 rev/s is not T, or it is, but I have to change it so it's in like m/s or something like that. If that's the case, then I need help finding that because I have no idea how to do that.

Thank you for any help!