Is My Chain Rule Derivation Correct for u*sin(x^2)?

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SUMMARY

The discussion focuses on the application of the chain rule to differentiate the function u*sin(x^2). The first derivative is correctly identified as u * 2x cos(x^2) + sin(x^2) u', while the second derivative is expressed as u * 2( x * -2sin(x^2) + cos(x^2)) + 2xcos(x^2)* u' + sin(x^2)*u" + u'* 2xcos(x^2). The consensus among participants confirms the correctness of these derivatives, assuming u is a function of x.

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I am trying to find the first and second derivative using the chain rule of the following:

u sin(x^2)

This is what I have but I don't think it is correct. Can someone pls let me know?

first derivative: u * 2x cos(x^2) + sin(x^2) u'

second derivative:
u * 2( x * -2sin(x^2) + cos(x^2)) + 2xcos(x^2)* u' + sin(x^2)*u" + u'* 2xcos(x^2)

Any help thanks
 
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If u is a function of x and you are differentiating with respect to x, then it looks correct to me.
 

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