The factor by which the acoustic power is changed is 7943.28

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SUMMARY

The acoustic power change factor calculated from a sound intensity level reduction from 80 dB to 41 dB is 7943.28. This was determined using the equation 10*log(I2/I1) = B1 - B2, where B1 is the initial intensity level and B2 is the final intensity level. The logarithmic calculation yielded a ratio of I2/I1 equal to 7943.28, confirming the significant reduction in acoustic power. This method effectively demonstrates the relationship between decibel levels and intensity ratios.

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Sound "Factor of"

Homework Statement



The intensity level of a particular sound coming through a medium gets reduced from 80 dB to 41 dB. By what factor is the acoustic power that can pass through changed by?

B1=80
B2=41

Homework Equations



10*log(\frac{I2}{I1}) = B1-B2

The Attempt at a Solution



I was wondering if I applied the correct method.

log(\frac{I2}{I1}) = 3.9

Using anti-log I get:
\frac{I2}{I1} = 7943.28
 
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Looks right to me.
 

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