Is My Solution Correct for Finding v0 Using Superposition Method?

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Discussion Overview

The discussion revolves around the application of the superposition method to find the voltage \( v_0 \) in a circuit. Participants are evaluating the correctness of a proposed solution and discussing the implications of Kirchhoff's Current Law (KCL) in the context of the circuit analysis.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents their solution using superposition and seeks validation of its correctness.
  • Another participant suggests using KCL at a node with three branches and derives a different value for \( v_0 \) (-1.00 V), which they confirm with a circuit-solving program.
  • A participant identifies mistakes in the equations used by the first poster, specifically regarding the sign of the voltage source and the total resistance calculation.
  • There is a mention of the correct approach to treating the voltage source when applying superposition, indicating that the current source should be replaced with an open circuit.

Areas of Agreement / Disagreement

Participants express differing views on the application of the superposition method and the correctness of the calculations. There is no consensus on the validity of the initial solution or the subsequent corrections proposed.

Contextual Notes

Some assumptions about circuit components and configurations may not be explicitly stated, and there are unresolved mathematical steps in the participants' reasoning.

noppawit
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I'm solving by using superposition, I would like to ask that my solution is correct or not.

By the way, the question is "Find v0"

http://www.wisheyebio.com/uploads/Picture1.png
 
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I don't know about superposition, but if you use KCL at the top node, you have three branches:

The left branch has the current source and two resistors.

The right branch has the voltage source and two resistors.

The middle branch has the remaining resistor.

KCL says that:

current going into node = current coming out of node

which, in this case means:

current in left branch + current in right branch = current in middle branch.

I called the current in the right branch i0, which makes v0 = i0R. I get a significantly different answer (-1.00 V), which I confirmed using a circuit-solving program.
 
noppawit said:
I'm solving by using superposition, I would like to ask that my solution is correct or not.

By the way, the question is "Find v0"

http://www.wisheyebio.com/uploads/Picture1.png
[/URL]

You made two mistakes in the second equation. Since [tex]i_x[/tex] is entering the plus sign of the voltage source, it should enter the equation as +9V, instead of -9V.
Also, [tex]R + R + \frac{2}{3}R = \frac{8}{3}R[/tex], not [tex]\frac{32}{3}R[/tex]
 
Last edited by a moderator:
IIRC, when treating the 9V source you would replace the current source with an open circuit, not a short. So the 2/3 R was incorrect to begin with.
 
Redbelly98 said:
IIRC, when treating the 9V source you would replace the current source with an open circuit, not a short. So the 2/3 R was incorrect to begin with.
You are right.
 

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