Is P4 a Subspace and What is Its Dimension?

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Homework Help Overview

The discussion revolves around the set P4, which consists of all real polynomials of degree less than or equal to 4. Participants are tasked with proving that P4 is a subspace of the vector space of all real polynomials and determining its dimension, which is suggested to be 5.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the properties of P4 as a vector space, discussing the requirements for a set to be a basis, including linear independence and spanning. There is an attempt to identify a potential basis set, specifically considering the polynomials (1, x, x², x³, x⁴).

Discussion Status

The discussion is ongoing, with participants questioning the definition of a basis and how to demonstrate that a proposed set is indeed a basis. Some guidance has been offered regarding the characteristics of a basis, but no consensus has been reached on the verification process.

Contextual Notes

Participants are navigating the definitions and properties of vector spaces and bases, with an emphasis on ensuring linear independence and spanning properties. There is a note about the notation used to represent sets and vectors in this context.

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Homework Statement


Consider the set P4 of all real polynomials if degree <= 4.

1)Prove that P4 is a subspace of the vector space of all real polynomials
2)What is the dimension of the vector space P4. Prove answer by demonstrating a basis and verifying the proposed set is really a basis.


Homework Equations


The Attempt at a Solution



1)Let the vector ##V = P={a_0+a_1x+a_2x^2+...+a_nx^n}## where the coefficients are real numbers

let ##p(x)=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4## ##q(x)=b_0+b_1x+b_2x^2+b_3x^3+b_4x^4##

Then (p+q)(x) =p(x)+q(x)= (a_0+b_0)+(a_1+b_1)x+(a_2+b_2)x^2+(a_3+b_3)x^3+(a_4+b_4)x^4

kp(x)=(kp)(x)=ka_0+ka_1x+ka_2x^2+ka_3x^3+ka_4x^4

thus p+q and kp are in V...?

2) Dimension is 5, ie we need 5 coefficients to have the basis linearly independent.
How do I demonstrate a basis and verify it?

Thanks
 
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bugatti79 said:
2) Dimension is 5, ie we need 5 coefficients to have the basis linearly independent.
How do I demonstrate a basis and verify it?
It sounds like you already have a guess how to find the coordinates of a polynomial with respect to a particular basis; you just haven't yet found the basis. What would the coordinates of a basis vector be?
 
Hurkyl said:
It sounds like you already have a guess how to find the coordinates of a polynomial with respect to a particular basis; you just haven't yet found the basis. What would the coordinates of a basis vector be?

Well the definition of a basis is that the basis set has to be linearly independent and it spans the vector V
So could we use ##(1,x,x^2,x^3,x^4)## since this is linearly independent.

Would the coordinates be the coefficients of ##(a_0,a_1x,a_2x^2,a_3x^3,a_4x^4)##...?
 
bugatti79 said:
Well the definition of a basis is that the basis set has to be linearly independent and it spans the vector V
So could we use ##(1,x,x^2,x^3,x^4)## since this is linearly independent.

Would the coordinates be the coefficients of ##(a_0,a_1x,a_2x^2,a_3x^3,a_4x^4)##...?

As you say the basis is a set. It is customary to use { } to denote a set. Take care not to make the assumption that you absolutely need a (... ,... , ) notation to denote vectors in this case c+bx+cx²+ ... is a vector.
 

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