I Is Probability in Quantum States Proportional to Energy Levels?

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The discussion centers on the relationship between quantum states and their probabilities, particularly whether the probability of a particle being in a certain state is proportional to the energy of that state. It clarifies that probabilities in quantum mechanics relate to measurement outcomes rather than the states themselves, emphasizing that knowing the energy states alone does not provide information about the system's state. If a system is prepared in a specific energy eigenstate, the probability of measuring that state is 1, while the probability for other states is 0. The conversation also touches on the limitations of applying statistical mechanics concepts, like the Boltzmann distribution, to isolated quantum systems. Ultimately, without knowledge of how a system was prepared, one cannot determine the probabilities of its energy states.
  • #31
bob012345 said:
I understand we can only measure eigenvalues. But we can certainly know the expectation value for the energy of the system.

If what you mean is "expectation value", then you need to say "expectation value". You can't just say "energy" and expect everyone to know that you mean "the expectation value of energy in some particular state that is not an eigenstate of energy".

bob012345 said:
I'm just trying to understand what that entails

You have been told two different ways what kind of preparation is necessary for a Boltzmann distribution to apply. I did in post #15, and @f95toli did in post #17. The two descriptions we gave are equivalent.

bob012345 said:
and how it would apply to a quantum system of a particle in a box?

It wouldn't. You have already been told why (@Nugatory did that in post #14).
 
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  • #32
The original question of this thread has been answered and I think I have synthesized in my mind all the answers given about that and the discussion of the Boltzmann distribution so I thank everyone for their answers.
 
  • #33
bob012345 said:
The original question of this thread has been answered and I think I have synthesized in my mind all the answers given about that and the discussion of the Boltzmann distribution so I thank everyone for their answers.

Thanks for the feedback! I'm glad we were able to answer your questions.
 
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