Is Qij=AiBj a Tensor of Rank 2?

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SUMMARY

The object Q defined by the components Qij=AiBj, where A and B are vectors, is confirmed to be a tensor of rank 2. This conclusion is reached by demonstrating that Q transforms under rotations according to the tensor transformation rule Tij'=RinRjmTnm. The transformation of the vectors A and B under rotations is essential to proving that Q retains its tensorial properties, specifically that Q'_{nm} = A_i' B_j' = R_{in} R_{jm} Q_{nm}.

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  • Understanding of vector transformations under rotations
  • Familiarity with tensor notation and properties
  • Knowledge of linear algebra concepts, particularly matrix operations
  • Basic understanding of tensor rank and its implications
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This discussion is beneficial for students and professionals in mathematics, physics, and engineering who are studying tensor analysis and its applications. It is particularly useful for those looking to deepen their understanding of tensor properties and transformations.

flintbox
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Homework Statement


Suppose A and B are vectors. Show that the object Q with nine components Qij=AiBj is a tensor of rank 2.

Homework Equations


A tensor transforms under rotations (R) as a vector:
Tij'=RinRjmTnm

The Attempt at a Solution


I wanted to just create the matrix, but I don't know how to prove that this is also a tensor.
 
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flintbox said:

Homework Statement


Suppose A and B are vectors. Show that the object Q with nine components Qij=AiBj is a tensor of rank 2.

Homework Equations


A tensor transforms under rotations (R) as a vector:
Tij'=RinRjmTnm

The Attempt at a Solution


I wanted to just create the matrix, but I don't know how to prove that this is also a tensor.
Well, how do the vectors ##A## and ##B## transform under rotations?
 
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Thanks a lot!
I think I understand it now:
$$A_i' B_j' = R_{in}A_n R_{jm}A_m$$
$$A_i' B_j' = R_{in} R_{jm} (A_n A_m)$$
$$A_i' B_j' = R_{in} R_{jm} Q_{nm}$$
$$A_i' B_j' = Q'_{nm}$$
So we for proving something is a tensor, we just apply some transformations to it, right?
 
flintbox said:
Thanks a lot!
I think I understand it now:
$$A_i' B_j' = R_{in}A_n R_{jm}A_m$$
$$A_i' B_j' = R_{in} R_{jm} (A_n A_m)$$
$$A_i' B_j' = R_{in} R_{jm} Q_{nm}$$
$$A_i' B_j' = Q'_{nm}$$
So we for proving something is a tensor, we just apply some transformations to it, right?

Yes, something is a tensor if it transforms like a tensor.
 

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