Is Replacing a 25 kVAr Unit with Two 12.5 kVAr Units More Efficient?

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SUMMARY

The discussion centers on the recommendation to replace a 25 kVAr power factor correction unit with two 12.5 kVAr units based on an analysis of interval data indicating a peak demand of 30 kVAr, often only requiring 12.5 kVAr. The recommendation aims to optimize power factor correction by allowing for more precise adjustments to varying load conditions. Economic justification for this change depends on whether the energy supplier charges for capacitive power factor, as some utilities do, while others do not.

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  • Understanding of power factor correction principles
  • Familiarity with kVAr and its significance in electrical systems
  • Knowledge of utility billing practices related to power factor
  • Basic concepts of reactive power and its implications
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AbdullahS
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TL;DR
Advice needed on Power Factor Correction Unit upgrade
Hi all,

The power factor correction unit for one of the buildings that I am working on needs maintenance. The service report recommends replacing the existing 25 kVAr unit with 2 x 12.5 kVAr units as "the demand on your site according to the data supplied shows us that at most there is only 30kVAr required at peak demand and quite often only requires 12.5kVAr".

This has been recommended after the analysis of interval data. The following graph shows the KVAr at the site for a period of 3 months.

1581896853254.png


Could you please advice if replacing the larger bank with two 2 smaller capacitor banks justified? If so, what is the reason? Shouldn't the old one do the job even when the kVAr requirement is low?

A bit of background about myself:
I am a mechanical engineer who is working in sustainability industry. I do have basic knowledge of reactive power but not detailed enough to answer questions such as these.

Thanks in advance.

Regards,
Abdullah
 
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Whether the change is a good economic decision (or not) depends primarily on how your energy supplier bills for Power Factor. In the simplest case, Power Factor correction systems add capacitance to 'offset' the inductive character of most loads. A 'too large' correction will leave your power factor 'too capacitive.' 2 smaller systems would allow closer to ideal (net zero) correction for a range of loads. As I understand it, some utilities charge for capacitive PF, and some don't - if yours does bill for capacitive PF, you'll need to compare the 'do nothing' cost to the cost of the new arrangement. If they don't bill for capacitive PF, you probably can't (economically) justify the change.
 
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Most likely this can only be answered by an "old timer". I am making measurements on an uA709 op amp (metal can). I would like to calculate the frequency rolloff curves (I can measure them). I assume the compensation is via the miller effect. To do the calculations I would need to know the gain of the transistors and the effective resistance seen at the compensation terminals, not including the values I put there. Anyone know those values?

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