Is Sigma(y(n)) Absolutely Convergent if y(n) = O(x(n))?

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SUMMARY

The discussion confirms that if the series sigma(x(n)) is absolutely convergent and y(n) is bounded by O(x(n)), then the series sigma(y(n)) is also absolutely convergent. This conclusion is derived from the definition of Big O notation, which indicates that y(n) does not grow faster than a constant multiple of x(n). Thus, the absolute convergence of sigma(x(n)) guarantees the absolute convergence of sigma(y(n)).

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penguin007
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Hi,

assume sigma(x(n)) is an absolutly convergent series and that y(n)=O(x(n)), then can we conclude that sigma(y(n)) is absolutly convergent?


thanks
 
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Yes. That is pretty close to being the definition of "O".
 
thanks again
 

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