Is the Calculation of Area Using Riemann Sum Correct?

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Homework Help Overview

The discussion revolves around calculating the area under the curve defined by the function y=2x^3+1, bounded by y=0, x=0, and x=2, using the limit of a Riemann sum. Participants are examining the correctness of the area calculation and the evaluation of the corresponding integral.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the application of the limit of a Riemann sum to find the area, with one participant questioning the original poster's result of 2. Others are evaluating the integral and expressing confusion over differing results obtained from the integral and the Riemann sum.

Discussion Status

The discussion is ongoing, with participants offering insights into the evaluation of the integral and the limit process. There is a recognition of multiple answers being derived, prompting further inquiry into the methods used to reach these conclusions.

Contextual Notes

Some participants are questioning the formulas and methods used for calculating the limit and the sum, indicating a potential lack of clarity or understanding regarding the application of these concepts in the context of the problem.

NIZBIT
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I was hoping someone could check my answer?

Use the limit of a Riemann sum to find the area of the region bounded by the graphs of y=2x^3+1, y=0, x=0, x=2.

Area=2
 
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The limit of the Riemann Sum is the integral. So evaluate [tex]\int_{0}^{2}2x^3+1dx[/tex]. I don't get 2. How did you do your problem?
 
A useful formaula is

[tex]\int_{a}^{b}f(x) \, dx = \lim_{n\rightarrow\infty} \frac{b-a}{n}\sum_{k=1}^{n}f\left( a+\frac{b-a}{n}k\right)[/tex]​

hence

[tex]\int_{0}^{2}(2x^3+1) \, dx = \lim_{n\rightarrow\infty} \frac{2}{n}\sum_{k=1}^{n}\left[ 2\left( \frac{2k}{n}\right) ^3 +1\right][/tex]​
 
Now I am getting two answers-10 for the def integral and 8 for the sum.
 
10 is obviously the correct answer. How are you taking the limit, as n goes to infinity on
[tex]\lim_{n\rightarrow\infty} \frac{2}{n}\sum_{k=1}^{n}\left[ 2\left( \frac{2k}{n}\right) ^3 +1\right][/tex]
?

Do you know a formula for the sum of k3, k2, and k that you are using?
 

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