Is the Canonical Map Z to Zsubscript5 1-1 and Onto?

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SUMMARY

The canonical map from Z (the set of all integers) to Z5 (the set of equivalence classes modulo 5) is established as onto but not one-to-one. This conclusion arises from the fact that Z encompasses all integers, while Z5 consists of the equivalence classes [0], [1], [2], [3], and [4]. The mapping fails to be one-to-one because multiple integers, such as 0 and 5, map to the same equivalence class [0]. A clear proof demonstrates that for any equivalence class [a] in Z5, there exists an integer in Z that maps to it.

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Punkyc7
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Determine if the canonical map Z to Zsubscript5 is 1-1 and onto. Prove your answer


Im not sure how to prove it but I am almost positive that its onto and not 1-1. I believe it onto because Z contains all the integers and Zsubscript5 contain the equivalence classes [0] [1] [2] [3] [4]. I don't believe that its 1-1 because 0 and 5 get mapped onto [0]
 
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Your proof looks good to me! You might want to be a bit more explicit about being onto. That is, if I give you the equivalence class [a], what integer gets mapped to [a] by the canonical map?
 

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