Is the Curl of Induced E Field Always Zero?

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SUMMARY

The curl of the electric field (E-field) is zero only in electrostatics, where the E-field is time-independent. In dynamic situations, the curl of the E-field is equal to the negative rate of change of the magnetic field (B-field), expressed mathematically as ∇ × E = -∂B/∂t. This indicates that the induced electric field, resulting from changes in magnetic flux, is non-conservative and can produce a path-dependent integral around a closed loop equal to the electromotive force (EMF) in the circuit. Therefore, the claim about the E-field having zero curl applies strictly to electrostatic conditions.

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Sturk200
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I have a problem. So the curl of the E field is supposed to be zero always, which tells us that it is a conservative force (path independence and scalar potential and so on). But what about the fact that the induced electric field consequent upon changes in magnetic flux is circular? Doesn't this mean that if we sustained such a field we would have a non-conservative electric field?

Is this a problem, or is it just that the claim about electric fields having zero curl has application only to electrostatics?
 
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Sturk200 said:
I have a problem. So the curl of the E field is supposed to be zero always, which tells us that it is a conservative force (path independence and scalar potential and so on). But what about the fact that the induced electric field consequent upon changes in magnetic flux is circular? Doesn't this mean that if we sustained such a field we would have a non-conservative electric field?

Is this a problem, or is it just that the claim about electric fields having zero curl has application only to electrostatics?

The curl of the E-field is zero only if the E-field is time independent, i.e. electrostatics. In the dynamic case, the curl of the E-field is the negative rate of change of the B-field, which is not zero in general. This makes the dynamic E-field non-conservative, with the path integral around a closed loop equal to the EMF in the circuit which drives the current.
 
Sturk200 said:
the curl of the E field is supposed to be zero always
No, ##\nabla \times E=-\partial B/\partial t##
 
Last edited:
DaleSpam said:
No, ##\nabla \times E=\partial B/\partial t##
Don't forget the negative sign.
 
MarcusAgrippa said:
Don't forget the negative sign.
Oops, fixed it.
 

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