Is the Infinite Series Convergent or Divergent Despite Initial Undefined Terms?

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Homework Help Overview

The discussion revolves around the convergence or divergence of two infinite series, one involving a rational function and the other involving a logarithmic function. The first series is questioned due to its undefined term at n=1, while the second series is analyzed using the Limit Comparison Test and the implications of including zero in a series.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore whether the first series can still be considered convergent despite being undefined at n=1, with some suggesting it may be convergent from n=2. The second series is discussed in terms of its divergence, with questions about the validity of using zero in convergence tests and the necessity of using terms beyond the first.

Discussion Status

There is ongoing exploration of the implications of undefined terms in series and the nature of convergence tests. Some participants provide guidance on the Limit Comparison Test and suggest alternative methods, while others emphasize that the convergence of a series is determined by its behavior as n approaches infinity.

Contextual Notes

Participants question the definitions and assumptions regarding positive series and the treatment of zero in convergence tests, indicating a need for clarification on these points.

tsw303
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Homework Statement



Convergent/Divergent?

Problem 1: infinite series, sigma(n=1) [1/((n^2)-n)
This one is clearly convergent, however it is undefined at n=1.
Is the whole problem undefined? Or is it convergent from (n=2)?


Problem 2: infinite series, sigma(n=1) [ln(n)/n]
This is divergent. It works with the Limit Comparison Test, but for some reason, I'm thinking I have to start by using sigma(n=2) [ln(n+1)/(n+1)] because, otherwise the first term would be zero. Can the test for a positive series include zero?


Homework Equations



Problem 1: Sn=(1/0)+(1/3)+(1/8)+...
Sn - undefined

Problem 2: Sn=(0/1)+(ln2/2)+(ln3/3)+...
(positive series?)

The Attempt at a Solution



Problem 1: Sn undefined => Series also undefined?

Problem 2: LCT, use b=(1/n), lim(n..inf) (a/b) = lim(n..inf) [(lnn/n)/(1/n)] = lim(n..inf) ln(n) = inf , limit > 0 , sigma (1/n) divergent, so sigma (lnn/n) divergent too.
Series divergent
 
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The convergance of a series only depends on what happens at the end.
 
tsw303 said:
Problem 1: infinite series, sigma(n=1) [1/((n^2)-n)
This one is clearly convergent, however it is undefined at n=1.
Is the whole problem undefined? Or is it convergent from (n=2)?

Yes, it's undefined. I think whoever wrote the problem botched this. You should ask your prof for clarification.

Problem 2: LCT, use b=(1/n), lim(n..inf) (a/b) = lim(n..inf) [(lnn/n)/(1/n)] = lim(n..inf) ln(n) = inf , limit > 0 , sigma (1/n) divergent, so sigma (lnn/n) divergent too.
Series divergent

The series does diverge, but you didn't prove it. In order for LCT to tell you anything, the limit has to come out to a finite, positive number. You won't get that here. Use the Integral Test instead.
 
Thank you. Much appreciated.

What about the term "positive series"? The convergence tests call for positive series, but problem 2 has a_1 = 0. I can use a_n+1 for the proof, but do I have to?
 
(...pardon me)

Is zero a positive number?
 
It really doesn't matter, because as foxjwill has pointed out, the convergence or divergence of a series only depends on what happens for large n. Deleting a finite number of terms from a series doesn't affect the convergence or divergence at all.
 
tsw303 said:
(...pardon me)

Is zero a positive number?

No, it isn't.
 
tsw303 said:
(...pardon me)

Is zero a positive number?
It's neither positive or negative.
 

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