Is the Kinetic Friction Coefficient Consistent Across Different Modes of Motion?

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SUMMARY

The discussion centers on the consistency of the kinetic friction coefficient (μ) when an object with mass (m) is subjected to different modes of motion—specifically, being pulled at a constant velocity versus being pushed and released. Measurements indicated a μ of 0.1573 when pulled and 0.2931 when pushed, raising questions about the accuracy of the results. The conclusion drawn is that the coefficient should remain constant across both scenarios, and discrepancies may arise from experimental errors, particularly if any force component acts upwards, reducing the normal force (Fn).

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  • Understanding of kinetic friction and its formula: Fk = μ * Fn
  • Basic knowledge of forces and motion, including normal force (Fn)
  • Familiarity with experimental measurement techniques and uncertainty analysis
  • Ability to interpret Force vs. Time graphs in physics experiments
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  • Research the factors affecting the kinetic friction coefficient in different scenarios
  • Learn about experimental error analysis and how to minimize uncertainties in measurements
  • Explore the effects of normal force variations on friction measurements
  • Investigate the principles of dynamics related to pulling and pushing forces
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Physics students, experimental physicists, and engineers interested in understanding friction dynamics and improving measurement accuracy in their experiments.

badsis
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Hello,

Here is my question:
should the kinetic friction coefficient Fk be the same when the object with mass m is pulled with a constant velocity as the kinetic friction coefficient with the same mass m when it was pushed and released.
The measurements in the second case were taken from the decelerating part of the Force vs. Time graph.

I have several table with data many of which i have calculated myself.
from the formula: Fk = ;mu * Fn
Fk - kinetik friction force,
;mu - coefficient of friction kinetic force
Fn - normal force
in the first case I have:
m = 0.09 kg
Fk = 0.1387 N (the uncertainty here is 17% ! Fk = 0.1387 +- 0.0238)
Fn = 0.882 N
=> ;mu = 0.1573

In the second case:
m = 0.09 kg
Fk = 0.2585 N
Fn = 0.882 N
=> ;mu = 0.2931
here i also have uncertainty in acceleration which I use in order to find Fk.

So, my question is: Should the coefficient ;mu be different in two cases or do I have such a big error?

THANKS!
 
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The coefficient should be the same. If you are pulling the mass be careful that no component of the force acts upwards since this will reduce the normal force.
 

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