Is the Normal Force Larger in a Box-Pushing Scenario?

AI Thread Summary
In a box-pushing scenario where a 250 N force is applied at a 20° angle below the horizontal, the normal force is indeed larger than the weight of the box. This is because the normal force must counteract both the gravitational force acting on the box and the downward component of the applied force. The calculation involves adding the gravitational force (Fg) to the vertical component of the applied force, which is determined using the sine function. As a result, the normal force exceeds the weight of the box to maintain equilibrium. Understanding this balance is crucial for applying Newton's laws correctly.
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Homework Statement



A box is being pushed across the floor with a 250 N force directed 20ο
below the horizontal. Is The normal force is larger than the weight of the box?

True or False.

Explain.

Homework Equations



sin(20) = opp/hyp

The Attempt at a Solution



Fn = 250sin(20o) + Fg

Please help explain how this problem is done, and why we would add Fg. Thank you.
 
Last edited:
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The force is being applied at an angle below the horizontal. Therefore, the normal force must counteract both the downward component of the applied force and the gravitational force.
 
But how do we know if it is greater than the weight of the object? Shouldn't it be equal?
 
the normal force is the perpendicular contact force of the floor acting on the box. It's value must be in accord with Newton's 1st law, per Precursor's response, and the equations you noted above in your initial post.
 
The normal force is greater than the weight because it has to balance both gravitational and applied force.
 

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