Is the Potential at the Negative Terminal of a Battery Always 0 V?

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The potential at the negative terminal of a battery is defined as 0 volts, regardless of the load or resistance in the circuit. Even with low resistance, the negative terminal remains at 0 volts, while the positive terminal can drop below its nominal voltage under heavy load conditions. The concept of "electron temperature" relates to both thermal and drift velocities, where a cold electron can gain energy through acceleration, affecting its overall energy state. Thermal energy increases with temperature, impacting electron behavior in circuits. Thus, the definitions of potential and electron temperature are crucial for understanding circuit dynamics.
Tinne
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Homework Statement



This is not a real existing homework problem but I do have two questions.

Q.1. In a circuit with a battery of 12 V, one always draws a scheme in which 0 V is written next to the negative terminal. Now, consider only a low resistance (and assume no short circuit will occur), is the potential at the negative terminal of the source near to 12 V (because of the low resistance) or is it always near to 0 V because the electrons lose/use their energy anyway, independing of the resistance they experience.

Q.2. The temperature of electrons is often written in electron volts (eV). The temperature, does it depend both on the thermal velocity and the drift velocity? So a cold electron (at room temp) can have a lot of energy if it is accelerated (or does the thermal energy increases as well then) and a slowly drifting electron with a high temperature also has a high "electron temperature"?

Homework Equations



thermal velocity: sqrt(3kT/m)
drift velocity: sqrt(2qV/m)

with V the potential difference.

The Attempt at a Solution



Hours of search to a simple explanation but nothing found so far.
 
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The potential at the negative terminal of the battery is always exactly 0 volts (for the cases you are considering). It is defined as being 0 volts, and doesn't change with the load. If the load draws a lot of current, the battery voltage will seem to drop, in which case the positive terminal is no longer delivering +12 volts, it may fall to +11 volts, or even less. Same thing happens when the battery is going flat.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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