Is the Series Ʃ n^4 / e^(n^2) Convergent?

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Homework Help Overview

The discussion revolves around determining the convergence of the series Ʃ n^4 / e^(n^2), focusing on the application of convergence tests such as the root test and ratio test.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the root test and the implications of limits involving n as it approaches infinity. There are suggestions to consider the ratio test and to clarify the notation used in the original post.

Discussion Status

Some participants express confidence in the original poster's approach while others suggest alternative methods for testing convergence. There is an ongoing exploration of different tests and their applications.

Contextual Notes

Participants note the importance of considering the domain of n and the implications of treating n as a real number versus natural numbers in limit evaluations.

ichilouch
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Homework Statement


determine whether the Ʃ n4 / en2 is convergent or divergent?


Homework Equations





The Attempt at a Solution


Using Root test:
lim of n4/n / en as n approaches infinity
But lim of n4/n as n approaches infinity = ∞0
So: Let N = lim of n4/n as n approaches infinity
and: ln N = lim of 4ln(n)/n as n approaches infinity = ∞/∞
By Lhopitals rule: ln N = lim 4/n as n approaches infinity = 0
thus ln N = 0 ; 1 = N
Therefore: lim of n4/n / en as n approaches infinity = 1/∞ = 0
thus CONVERGE?

Is this solution Ok?
 
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The notation could be improved (might be the conversion to text here), but the method is fine.
Be careful with the domain of n when you check the limit of n^(4/n): you want the limit for natural numbers, but then you treat n as a real number. This is possible (a limit for real numbers for n->infinity is also a limit for natural numbers), but you have to consider it.
 
I think it's correct. For practice, try using the ratio test using inequalities.
 
Are there another way on how to test the convergence of this series?
 
Yes. Take the ratio test. Then use the definition of Euler's constant

e=\lim_{n\rightarrow \infty}\left(n+\frac{1}{n}\right)^n

to find where the limit lies
 

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