Is the Set of 3x3 Matrices Annihilating a Given Vector a Subspace?

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SUMMARY

The set of 3x3 matrices A that annihilate the vector <1,2,3> forms a subspace of R^(3x3). This is established by demonstrating that the subset V={A|A*<1,2,3>=0} satisfies the conditions of a subspace: it contains the zero matrix, is closed under addition, and is closed under scalar multiplication. Specifically, if U and W are matrices in V, then any linear combination aU + bW also belongs to V, confirming the subspace properties.

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Homework Statement


Are the 3X3 matrices A such that vector <1,2,3> is in the kernel of A, a subspace of R^(3X3)?

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The Attempt at a Solution


I know that the kernel condition gives a subset V={A|A*<1,2,3>=0} but I am not sure of how to proceed to show it is in fact a subspace. Should I try to see if it spans or use the definition of a subspace? I'm just confused on how to proceed with the next step
 
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To show that it's a subspace, you have to show that if it contains u and v, then it contains au + bv where a and b are scalars, that it contains 0 and that it contains -u for any u that it contains.
 
To expand slightly on what aPhilosopher said, let U and W be matrices in your subset V. It's sufficient to show that aU + bW is also in the same subset, for any scalars a and b.

Showing that the subset contains the zero matrix corresponds to a = b = 0. Showing that -U is in the subset corresponds to a = -1 and b = 0.
 

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