Is the Solution to dx/dt=f(x) with x(0)=xo Unique?

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SUMMARY

The uniqueness of the solution to the differential equation dx/dt=f(x) with the initial condition x(0)=xo is established under the condition that f is in C^1(R), meaning that f has a continuous first derivative. The discussion demonstrates that if phi1(t) and phi2(t) are both solutions, then their difference satisfies the equation d(phi1(t)-phi2(t))/dt=f(phi1(t))-f(phi2(t)). This leads to the conclusion that phi1(t) must equal phi2(t), confirming the uniqueness of the solution. Additionally, every solution x(t) must satisfy F(x(t))=t, where F is defined as the integral from xo to x of (dy/f(y)).

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Homework Statement


Show that the solution of dx/dt=f(x), x(0)=xo, f in C^1(R), is unique


Homework Equations


C^1(R) is the set of all functions whose first derivative is continous.
F(x)=integral from xo and x (dy/f(y))

The Attempt at a Solution



Assume phi1(x) and phi2(x) are both soultions. Then d(phi1(x))/dt=f(phi1(x)) and d(phi2(x))/dt=f(phi2(x)). Consider phi1(x)-phi2(x). d(phi1(x)-phi2(x))/dt= f(phi1(x))-f(phi2(x))...
I need to prove the two solutions are infact equal. Also it says in my book that every solution x(t) must satisfy F(x(t))=t, with phi(t)=F^-1 (t) (F Inverse)
 
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shouldn't the two solutions be functions of t?
 
yes. I am sorry. I made a mistake. the two solutions hsould be phi1(t) and phi2(t).
 

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