Linear algebra: Find the span of a set

Click For Summary

Homework Help Overview

The discussion revolves around finding the span of two sets: U, which consists of the functions {2, cos x, sin x} for x in the real numbers, and V, a set of vectors in a real n-dimensional space defined by parameters a and b. Participants are exploring the implications of linear independence and dimensionality in the context of function spaces and vector spaces.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants assert that the functions in U are linearly independent and span a three-dimensional space of functions, while others question the validity of this claim in relation to the dimensionality of the function space. There are discussions about the implications of the parameters a and b in set V, particularly regarding linear dependence and the dimensionality of the span.

Discussion Status

The discussion is ongoing, with participants providing insights and corrections regarding the dimensionality of the spans of U and V. Some have offered clarifications about the nature of the spaces involved, while others are questioning assumptions and exploring different interpretations of the problem.

Contextual Notes

Participants are navigating the distinction between function spaces and traditional vector spaces, highlighting potential misunderstandings about the dimensionality of the spans in relation to the definitions provided in the problem statement.

gruba
Messages
203
Reaction score
1

Homework Statement


Find the span of U=\{2,\cos x,\sin x:x\in\mathbb{R}\} (U is the subset of a space of real functions) and V=\{(a,b,b,...,b),(b,a,b,...,b),...,(b,b,b,...,a): a,b\in \mathbb{R},V\subset \mathbb{R^n},n\in\mathbb{N}\}

Homework Equations


- Span
-Subset

The Attempt at a Solution


[/B]
Objects in U :2,\cos x,\sin x are linearly independent, so they span \mathbb{R^3}.

Let ,n=3\Rightarrow [V]= \begin{bmatrix}<br /> a &amp; b &amp; b \\<br /> b &amp; a &amp; b \\<br /> b &amp; b &amp; a \\<br /> \end{bmatrix}

rref[V]=\begin{bmatrix}<br /> 1 &amp; 0 &amp; 0 \\<br /> 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 1 \\<br /> \end{bmatrix}\Rightarrow vectors in V span \mathbb{R^3}, if a,b\neq 0.

But because V\subset\mathbb{R^n}\Rightarrow vectors span \mathbb{R^{n-1}}.

Is this correct?
 
Physics news on Phys.org
gruba said:

Homework Statement


Find the span of U=\{2,\cos x,\sin x:x\in\mathbb{R}\} (U is the subset of a space of real functions) and V=\{(a,b,b,...,b),(b,a,b,...,b),...,(b,b,b,...,a): a,b\in \mathbb{R},V\subset \mathbb{R^n},n\in\mathbb{N}\}

Homework Equations


- Span
-Subset

The Attempt at a Solution


[/B]
Objects in U :2,\cos x,\sin x are linearly independent, so they span \mathbb{R^3}.
Yes.
gruba said:
Let ,n=3\Rightarrow [V]= \begin{bmatrix}<br /> a &amp; b &amp; b \\<br /> b &amp; a &amp; b \\<br /> b &amp; b &amp; a \\<br /> \end{bmatrix}

rref[V]=\begin{bmatrix}<br /> 1 &amp; 0 &amp; 0 \\<br /> 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 1 \\<br /> \end{bmatrix}\Rightarrow vectors in V span \mathbb{R^3}, if a,b\neq 0.
I don't know how valid your argument is, here. It's given that ##V \subset \mathbb{R}^n##. Can you extend this to a statement about an n-dimensional space instead of a 3-dimensional space?
gruba said:
But because V\subset\mathbb{R^n}\Rightarrow vectors span \mathbb{R^{n-1}}.

Is this correct?
Why do you conclude that the vectors span ##\mathbb{R}^{n - 1}##?
 
gruba said:

Homework Statement


Find the span of U=\{2,\cos x,\sin x:x\in\mathbb{R}\} (U is the subset of a space of real functions) and V=\{(a,b,b,...,b),(b,a,b,...,b),...,(b,b,b,...,a): a,b\in \mathbb{R},V\subset \mathbb{R^n},n\in\mathbb{N}\}

Homework Equations


- Span
-Subset

The Attempt at a Solution


[/B]
Objects in U :2,\cos x,\sin x are linearly independent, so they span \mathbb{R^3}.
They aren't even in ##\mathbb{R}^3##; they belong to a space of real functions.
 
To clarify/correct my "Yes" in post #2, the functions span a three-dimensional space of functions, not ##\mathbb{R}^3##.
 
Objects in U :2,\cos x,\sin x are linearly independent, so they span \mathbb{R^3}.
Yes, these vectors are linearly independent.
No, these vectors span a space isomorphic to \mathbb{R}^3

Regarding V. If a=b, then all of those vectors are linearly dependent. If a=0, then the vectors will span a null space. If a\neq 0, then the system of vectors will be reduced to only one vector and so it would span \mathbb{R}^1\subset \mathbb{R}^n
If a\neq b, then all of the vectors are in fact linearly independent: one can construct an n x n matrix of said vectors and reduce it to a diagonal matrix.
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
15
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K