If [tex]\phi[/tex] depends on a single position only, [tex]\phi=\phi(x,y,z)[/tex]
Can I say that:
Provided that the point a lies on the closed path being integrated around?
The Attempt at a Solution
I am 99.99% sure I can. I am in the middle of "showing" how one theorem implies another, and I wasn't sure if I could knock the partial dx off with the total dx in any case under the conditions above. Thanks for any help. (Sorry, I can't seem to get my latex correct. The second to last term is intended to be phi evaluated from a to a. Also the title should read "Is this true for any scalar function")