Is the voltage from point A to B equal to the voltage across R2?

EvLer · Mar 5, 2005

Hi all, I am asking to see if I understand voltage correctly:
This is what circuit looks like:

Code:

-----R1---A----R2---
|           +      |
Vs         v(t)    |
|           -      |
|_________B_______ |

As I see it, v(t)(voltage drop from A to B) is voltage across R2, is it correct?
Thank in advance.

formulajoe · Mar 5, 2005

that is correct

Corneo · Mar 5, 2005

What? the sum of the voltage drop from R1 and R2 is equal to the EMF (battery).

EvLer · Mar 5, 2005

Didn't want to start another thread, but now I have another question: after the switch in some circuit moves to a certain position I get following circuit:

Code:

 A-------R1--------------
                |        |
                |        |
             indctr     R2
                |        |
                |        |
 B-----------------------

Then voltage drop from A to B is sum of voltages across R1 and inductor (or R2), right? Then there is a current coming from A and divides into 2 (for inductor and R2)? Or does R1 not have any current?
Thanks again.

formulajoe · Mar 5, 2005

drop from A to B is Vr1 and 2*Vr2. Even though the inductor and r2 voltages are the same, they both must be added.

EvLer · Mar 5, 2005

Why 2*VR2? they are in parallel. What am I missing here? Don't inductor and R2 follow KVL?

formulajoe · Mar 5, 2005

oops, my bad. youre right. its just one.

EvLer · Mar 5, 2005

Oh, Ok, thanks!

Is the voltage from point A to B equal to the voltage across R2?

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