Calculate the voltage, current, and power across the two resistors for every second of run 1 in the RC circuit.
The RC Circuit:
The settings of the circuit:
The Graph. The capacitor is charged until it reaches 5.0 V and then discharged until it reaches 1.0 V. This process occurs four times total.
VC = ξ * (1 - e-t/RC)
(Not sure about others.)
The Attempt at a Solution
This is a lab more so than a question and therefore doesn't necessarily have an exact answer. I am having trouble with the process of getting an answer.
I have eyeballed the voltages from the graph for every second but am unsure how to calculate the voltage across each resistor. Is the voltage in each resistor the same as the voltage that is currently in the capacitor at time that time s?
I tried calculating the time constant by plugging the capacitor voltage at 5 seconds with a emf of 6.0 V and got 2.79 seconds, but 63% of 6.0 V is 3.78 V and eyeballing the graph I get approx. 2 seconds to reach 63% max voltage.
I feel like I am overthinking this and am unconfident in my knowledge of this section in my textbook, but rereading isn't helping me either.