Is the Work Calculation for Overcoming Friction Correct?

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SUMMARY

The work calculation for overcoming friction in the discussed scenario is incorrect. The applied force of 52 N on a 12 kg mass results in a net force of 37 N when accounting for the 15 N friction force. The correct work done to overcome friction while moving the object 24 m is calculated as 24 m multiplied by the friction force of 15 N, resulting in 360 J. Therefore, the work done to overcome friction is -360 J, reflecting the energy required to maintain constant velocity against friction.

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Brittykitty
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A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


w=fd
w=(37N)(24m)
w=888J


Does this procedure seem correct ? :) Thank you!
 
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No. You have calculated the net force and net (total) work done on the object. The total work done on the object includes the work done by the applied 52 N force, and the work done by the friction force. The work done to overcome friction is the work necessary to keep the object moving at constant velocity.
 
What formula would I use to find the work done to overcome friction? I sort of understand but am still a bit confused
 
The work done to overcome friction while moving the block 24 m is the negative of the work done by friction while moving the block 24 m.
 
So it would be -888J?
 
24m*15N=360?
 
Brittykitty said:
24m*15N=360?
360 J, yes.
 

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