Is the Work Calculation for Overcoming Friction Correct?

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Homework Help Overview

The discussion revolves around calculating the work done to overcome friction when a force is applied to a mass. The subject area includes concepts of work, friction, and net forces in physics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the calculation of work done against friction, questioning the original poster's method and discussing the correct interpretation of forces and work in this context.

Discussion Status

There is an active exchange of ideas regarding the correct approach to calculating work done against friction. Some participants provide clarifications on the relationship between applied force and friction, while others express confusion about the formulas and calculations involved.

Contextual Notes

Participants are navigating through the implications of net forces and the specific work done against friction, with some uncertainty about the definitions and calculations required.

Brittykitty
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A force of 52 N is applied to a 12 kg mass resting on a bench where the force of sliding friction is 15 N. The work done in overcoming friction while moving the object 24 m is


w=fd
w=(37N)(24m)
w=888J


Does this procedure seem correct ? :) Thank you!
 
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No. You have calculated the net force and net (total) work done on the object. The total work done on the object includes the work done by the applied 52 N force, and the work done by the friction force. The work done to overcome friction is the work necessary to keep the object moving at constant velocity.
 
What formula would I use to find the work done to overcome friction? I sort of understand but am still a bit confused
 
The work done to overcome friction while moving the block 24 m is the negative of the work done by friction while moving the block 24 m.
 
So it would be -888J?
 
24m*15N=360?
 
Brittykitty said:
24m*15N=360?
360 J, yes.
 

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