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Is there a way to simplify a^log n, a = 1 / b

  1. Sep 14, 2011 #1
    Is there a way to simplify a^logn, a = 1 / b

    I don't know if this is possible, but I thought I would ask for another opinion if i'm overlooking something. Anyway, is there a way to simplify alogbn, a = 1 / b
     
  2. jcsd
  3. Sep 14, 2011 #2
    Re: Is there a way to simplify a^logn, a = 1 / b

    yes

    [itex]\left(b^{-1}\right)^{log_{b} n} = \left(b^{log_{b} n}\right)^{-1} = n^{-1}[/itex]


    as

    [itex]\left(b^{x}\right)^{y} = \left(b^{y}\right)^{x}[/itex]
     
    Last edited: Sep 14, 2011
  4. Sep 14, 2011 #3
    Re: Is there a way to simplify a^logn, a = 1 / b

    aha! thanks!
     
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