Is There an Easier Method for Solving Truss Problems?

  • Thread starter Thread starter yecko
  • Start date Start date
  • Tags Tags
    Section
Click For Summary
The discussion centers on the challenges of solving truss problems using the method of sections, particularly under time constraints during exams. The original poster expresses concern about the complexity of calculations involving lengths and slopes, seeking simpler methods for solving these problems. A response highlights a potential oversight in the original calculations, specifically the omission of an applied load in the force summation. The conversation emphasizes the need for efficient techniques to handle truss problems effectively within limited time. Overall, participants are exploring ways to simplify the problem-solving process for truss analysis.
yecko
Gold Member
Messages
275
Reaction score
15

Homework Statement


7F9F38F7-E1D4-4C7F-A665-4377358C4063.jpeg


Homework Equations


Method of section

The Attempt at a Solution


This pic below is my attempt, almost solved out length of all the truss... (and i am not sure if my numbers are correct as well for such a troublesome method in solving... )

as my exam would only leave me 15 minutes for each question, so it would be unlikely that i could solve it out with the same method during exam... i am sure there would be simpler ways to solve it...

can anyone suggest any better method to attempt the question?
Thank you very much!

FC77E2DF-BBFF-45E3-9238-81F4FACA6F4F.jpeg
 

Attachments

  • FC77E2DF-BBFF-45E3-9238-81F4FACA6F4F.jpeg
    FC77E2DF-BBFF-45E3-9238-81F4FACA6F4F.jpeg
    53.6 KB · Views: 448
  • 7F9F38F7-E1D4-4C7F-A665-4377358C4063.jpeg
    7F9F38F7-E1D4-4C7F-A665-4377358C4063.jpeg
    17.7 KB · Views: 949
Last edited:
Physics news on Phys.org
It is a bit of a pain to calculate lengths and slopes using geometry and trig. I'm not sure where yourverrir might be in the geometry, if any, but when you summed forces in the y direction, you forgot to include the applied load L.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
7
Views
1K
Replies
3
Views
7K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
25
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
1K