freshbox
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I'm sorry I still don't understand. What acceleration got to do with netforce?
The discussion revolves around a problem related to impulse and momentum in a linear dynamics context, specifically focusing on parts c and d of a homework question involving forces acting on a hammer and pile system. Participants are checking the correctness of their answers and exploring the implications of various forces, including gravity and resistive forces.
Some participants have provided insights into the forces acting on the hammer and pile, while others express confusion about the relationships between these forces and the net force. There is ongoing exploration of how to set up equations to solve for the resistive force and clarify the role of gravity in the context of the problem.
Participants are grappling with the definitions and roles of various forces, including the gravitational force and the net force, as well as how these relate to the impulse-momentum principle. There is mention of specific values and conditions, such as the mass of the hammer and the external forces involved, which may influence the calculations.
freshbox said:I'm sorry I still don't understand. What acceleration got to do with netforce?
I don't quite understand your question. It is the net force on a body that determines its change in motion.freshbox said:So I1-2= Force x Time
This is the net force but what does it represent as?
I got confused with this question part a (i). I know how to solve this question, I tried to used the same method and got the answer. But when I tried it on the previous hammer question with the working of:
This 3 marks is so damn hardOnce again: F is the net force, but they ask for the resistive force. So use the net force to solve for the resistive force. (Review post #28)freshbox said:I got confused with this question part a (i). I know how to solve this question, I tried to used the same method and got the answer. But when I tried it on the previous hammer question with the working of:
M1=mv
=(9000)(8.82)
=79380
M2=mv
=0
I1-2=Force x Time
=(F)(0.1)
=0.1F
M1+I1-2=M2
79380-0.1F=0
79380=0.1F
F=793800 Ans Wrong
Because you said this is the net force and plus the rest of the explanation totally make me lost in spaceThis 3 marks is so damn hard
In this case, the net force is the 'net resistive force', so that's your answer.freshbox said:Post #35 Question 7ai working:
M1=mv
=1000x19.44
=19444.44
M2=mv
=1000x16.67
=16666.67
T1-2= F x T
=-Fx4
=-4F
M1+I1-2=M2
19444.44-4F=16666.67
-4F=-2777.77
F=694.4N Answer
So this 694.4N is the net force, and there is another resistive force?
In the hammer question you had two individual forces acting: gravity and the resistive force of the ground.I tried to apply this style of working on the hammer question, but you told me that is the net force and ask me to find the other resistive force
I got confused here with this part and the hammer question, I hope you know what i meant...
